If point d (6-5m, m-2) is on the bisector of the second quadrant coordinate axis, then M= Given that point P1 (a, 3) and point P2 (- 2, b) are symmetric about y axis, then a =, B = If the coordinates of point P are (1-A, - 1 + a), then a

If point d (6-5m, m-2) is on the bisector of the second quadrant coordinate axis, then M= Given that point P1 (a, 3) and point P2 (- 2, b) are symmetric about y axis, then a =, B = If the coordinates of point P are (1-A, - 1 + a), then a

m=1
a=2
b=3
Delta Quadrant

Little sister a junior high school mathematics problem, will help me to solve
1/2*4+1/4*6+1/6*8+.1/198*200=?
There should be detailed steps ~ ~ thank you

=1/2(1/2-1/4+1/4-1/6+1/6-1/8+.+1/198-1/200)
=1/2(1/2-1/200)
=1/2(99/200)
=99/400

(13 of 18 * 5.16 + 516% * 3 of 18) △ 5 and 4 of 25

(13 of 18 * 5.16 + 516% * 3 of 18) △ 5 and 4 of 25
=5.16×(13/18+3/18)×4/129
=5.16×8/9×4/129
=1.28/9
=32/225

1*2*3*4*5*6…… How many zeros are there in 2003 * 2004

First of all, "how many zeros in all" cannot be answered unless it is calculated. However, how many zeros at the end can be calculated
Because 1 * 2 * 3 * 4 * 5 * 6 In 2003 * 2004, the number of 2 is much more than that of 5, so the number of 0 at the end is the same as that of 5
The number of times of 5 is calculated as follows:
In 2004, there are 400 multiples of 5
In 2004, there are 80 multiples of 25
In 2004, there are 16 multiples of 125
There are three multiples of 625 in 2004
There is no quintic power of 5 or higher power multiple of 5 in 2004
So 1 * 2 * 3 * 4 * 5 * 6 In 2003 * 2004, the times of 5 were as follows:
400 + 80 + 16 + 3 = 499
So the product 1 * 2 * 3 * 4 * 5 * 6 At the end of 2003 * 2004, there were 499 0

Read the following material: matching a quadratic trinomial (or part of it) in the form of AX2 + BX + C into a complete square is called matching method. The basic form of the formula is the inverse application of the complete square formula, that is, A2 ± 2Ab + B2 = (a ± b) 2. For example, x2-2x + 4 = (x-1) 2+______ x2-2x+4=（x-2）2+______ x2-2x+4=（12x-2）2+34______ According to the reading materials, solve the following problems: (1) copy the above examples, write three different forms of formula of x2-4x + 4; (2) write A2 + AB + B2 formula (at least write two forms); (3) known A2 + B2 + c2-ab-6b-6c + 21 = 0, find a , B, C

(1) The three formulas of x2-4x + 2 are: x2-4x + 2 = (X-2) 2-2, x2-4x + 2 = (x + 2) 2 - (22 + 4) x, x2-4x + 2 = (2x-2) 2-x2; (2) A2 + AB + B2 = (a + b) 2-AB = (a + 12b) 2 + 34b2; (3) ∵ A2 + B2 + c2-ab-6b-6c + 21 = a2-ab + 14b2 + 34b2-6b + 12 + c2-6c

(5 / 14-3 / 14 divided by 3 / 4) divided by 15 / 49
Simple calculation

(5 / 14-3 / 14 divided by 3 / 4) divided by 15 / 49
=(5 / 14-4 / 14) divided by 15 / 49
=1 / 14 divided by 15 / 49
=7/30

If a and B are two unequal real roots of the equation x & # 178; + x-2113 = 0, then the value of a & # 178; + 2A + B is_

A square + a-2113 = 0
B square + b-2113 = 0
By subtracting the two formulas, we get the following result:
(a-b Square) + (a-b) = 0
(a－b)(a＋b＋1)=0
Because a ≠ B, then: a + B + 1 = 0, that is: a + B = - 1
A square + 2A + B
=(a square + a) + (a + b)
=2013－1
=2012
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There is a formula cos θ = what divided by what

A1X+B1Y+C1=0.(1)
　　A2X+B2Y+C2=0.(2)
Formula of angle between two straight lines: cos φ = (A1A2 + b1b2) / [√ (A12 + B12) √ (A22 + B22)]

Cut a 3-meter-long cuboid wood into three sections on average, and increase its surface area by 100 square decimeters. How many cubic decimeters is the original volume of the wood?

The formula = (number of segments-1) x2
100 △ 4 = 25 (decimeter)
3 meters = 30 decimeters
25x30 = 750 (cubic decimeter)

Nine inches plus one inch equals one foot

Advance by an inch