If f (x) = Tan (Wx + π / 3) (W > 0), the length of the line segment of two adjacent sectional lines y = π / 4 is π / 4 (1) The analytic formula of ball f (x) and the value of F (π / 4) (2) Find the monotone interval of F (x)

If f (x) = Tan (Wx + π / 3) (W > 0), the length of the line segment of two adjacent sectional lines y = π / 4 is π / 4 (1) The analytic formula of ball f (x) and the value of F (π / 4) (2) Find the monotone interval of F (x)


1、
There is a period difference between two adjacent branches
So t = π / 4
So π / w = π / 4
w=4
So f (x) = Tan (4x + π / 3)
f(π/4)=tan(π+π/3)
=tan(π/3)
=√3
2、
TaNx is an increasing function in a period
Then K π - π / 2



The function f (x) = Tan ω x (ω > 0) has two adjacent tangent lines y = π 4. If the length of the line is π 4, then the value of F (π 4) is ()
A. 0B. 1C. -1D. π4


The length of the line segment obtained from the two adjacent tangent lines y = π 4 of the function image is π 4. The period of the function f (x) is π 4. From π ω = π 4, we get ω = 4. So we choose a



If the function f (x) = tanwx (W > 0), the length of the line segment is 6 π
Finding f (π / 2)


You know, tangent function image is a continuous translation
Period = π / w = 6 π
w=1/6
F (π / 2) = Tan π / 12 = 2-radical 3



Application of discriminant for roots of quadratic equation with one variable
Let a, B and C be the lengths of the three sides of △ ABC, and try to judge the roots of the quadratic equation A & sup2; X & sup2; + (B & sup2; + A & sup2; - C & sup2;) x + B & sup2


Discriminant = (b ^ 2 + A ^ 2-C ^ 2) ^ 2-4a ^ 2B ^ 2
=(b^2+a^2-c^2+2ab)(b^2+a^2-c^2-2ab)
=[(a+b)^2-c^2][(a-b)^2-c^2]
=(a+b+c)(a+b-c)(a-b+c)(a-b-c)
The side length of triangle is greater than 0
So a + B + C > 0
The sum of the two sides of a triangle is greater than the third side
So a + B-C > 0
a-b+c>0
a-b-c=a-(b+c)



What are real numbers and imaginary numbers?
I just want to know in advance!


Plural
Complex number: is the general name of real number and imaginary number. The basic form of complex number is a + bi, where a and B are real numbers, a is real part, Bi is imaginary part, I is imaginary unit. On the complex plane, a + bi is point Z (a, b). Real number: the general name of complex number, rational number and irrational number without imaginary part



Given that one root of the quadratic equation XX + MX + n = 0 with real coefficients is 1-3i, find the value of M + n


One root is 1 -- 3I, and the other root must be 1 + 3I,
So m = -- [(1 + 3I) + (1 -- 3I)] = -- 2,
n=(1+3i)(1--3i)=10,
So m + n = 8



The two roots of a quadratic equation with coefficient 1 are 2 and 3 respectively
How much can you write when the coefficient of quadratic term is not unique?


Y=(x-2)(x-3)
When the coefficient of quadratic term is not unique, we can write innumerable
Y=a(x-2)(x-3)



Three analytic geometry problems about circle,
1. Let a be the moving point on the circle (X-2) ^ 2 + (Y-2) ^ 2 = 1, then the maximum distance from a to the line x-y-5 = 0 is?
2. The equation of the circle passing through the intersection of the circle x ^ 2 + y ^ 2-x + Y-2 and x ^ 2 + y ^ 2 = 5 with the center of the circle on the straight line 3x + 4Y = 1 is?
3. Given that a circle passes through two intersections of (line 2x + y + 4 = 0 and circle C: x ^ 2 + y ^ 2 + 2x-4y + 1 = 0) and has the smallest area, the equation of the circle is?
I will answer a question. Help!


1+5√2/2
(x+1)^2+(y-1)^2=25/2
(x+13/5)^2+(y-6/5)^2=4/5



Given that a (- 2,0), B (2,0), and point P move on the circle (x-3) &# 178; + (y-4) &# 178; = 4, then the minimum value of | PA | &# 178; + | Pb | &# 178; is obtained


Let P (3 + 2 cosa, 4 + 2 Sina), then PA ^ 2 = (5 + 2 COSA) ^ 2 + (4 + 2 Sina) ^ 2 = 25 + 20 cosa + 4 (COSA) ^ 2 + 16 + 16 Sina + 4 (Sina) ^ 2 = 20 cosa + 16 Sina + 45, Pb ^ 2 = (1 + 2 COSA) ^ 2 + (4 + 2 Sina) ^ 2 = 4 cosa + 16 Sina + 21, PA ^ 2 + Pb ^ 2 = 24 COA + 32 Sina + 66 = 40 sin [a + arctan (3 / 4



Simple, don't tell me to use the formula of distance from point to line


The straight line y = KX + B, the slope is k, and the known point is a (a, b)
Let the symmetric point be p (x, y), then the coordinates of the midpoint of AP are x '= (x + a) / 2, y' = (y + b), which must be on y = KX + B, and then a equation (1) is obtained
If AP is perpendicular to y = KX + B, then the slope of AP = - 1 / K, that is, (y-b) / (x-a) = - 1 / K, (2)
(1) (2) get the P coordinate