A small square with X (CM) side length is subtracted from the four corners of a rectangular sheet of iron with the ratio of length to width of 2:1, and folded to make an open iron box If the sheet width is a (CM) (a > 2x), the volume of the iron box can be calculated

A small square with X (CM) side length is subtracted from the four corners of a rectangular sheet of iron with the ratio of length to width of 2:1, and folded to make an open iron box If the sheet width is a (CM) (a > 2x), the volume of the iron box can be calculated


The length, width and height of the iron box are 2a-2x, a-2x and X respectively
Therefore, the volume of the iron box is
(2a-2x)(a-2x)x