A rectangular iron sheet (as shown in the figure), 25 cm long and 15 cm wide, cut out the small square with side length of 2 cm from the four corners, and then fold it around to make an iron box without a cover. Please help to calculate: how much iron sheet does it need to make such a box? What is the volume of the iron box?

A rectangular iron sheet (as shown in the figure), 25 cm long and 15 cm wide, cut out the small square with side length of 2 cm from the four corners, and then fold it around to make an iron box without a cover. Please help to calculate: how much iron sheet does it need to make such a box? What is the volume of the iron box?


Solution: 25 × 15-2 × 2 × 4, = 375-16, = 359 (square centimeter); (25-2-2) × (15-2-2) × 2, = 21 × 11 × 2, = 462 (cubic centimeter); answer: to make such a box needs at least 359 square centimeter iron sheet, and the volume of the iron box is 462 cubic centimeter



There is a 25 cm long, 15 cm wide rectangular cardboard, if the four corners of the cardboard cut a small square of the same size, and then fold up the four sides
Make a cuboid box with a bottom area of 231 cm2. Solve the side length of the small square


Let the side length of a small square be x cm, and we get (* is multiplied by)
25 * 15-4x square - 2 * (25-2x) x-2x (15-2x) x = 231
The solution is X1 = 2, X2 = 18 (round)
A: the side length of a small square is 2 cm