If the perimeter of a parallelogram is equal to that of a rectangle, the area of the parallelogram must be smaller than that of the rectangle______ ．

If the perimeter of a parallelogram is equal to that of a rectangle, the area of the parallelogram must be smaller than that of the rectangle______ ．

As shown in the figure: area of rectangle = length × width, area of parallelogram = bottom × height. It can be assumed that length of rectangle = bottom of parallelogram, width of rectangle = a hypotenuse of parallelogram, then width of rectangle is greater than height of parallelogram, so length × width > bottom × height, then area of rectangle is greater than area of parallelogram, so the answer is: correct

The base of a rectangle and a parallelogram are equal in length and area
The perimeter of the rectangle is longer than that of the parallelogram, shorter, or equal. Please explain in detail. Big brother and big sister help me. I went to bed at 9:30!
So the answer is shorter than the perimeter of a parallelogram, right?

The perimeter of the rectangle is small, the area of the rectangle is equal to the base times the height, and the area of the parallelogram is the same as their height. In the triangle, the hypotenuse is the longest
In other words, the height of a rectangle is equivalent to a right angle side, and the hypotenuse of a parallelogram is equivalent to the hypotenuse of a triangle

Can a rectangle and a parallelogram have the same perimeter and area?
Let's take an example!

Even if it is a general parallelogram, it is possible
For example, the length and width of a rectangle are 8 and 4 respectively, its area is 32, and its perimeter is 2 * (8 + 4) = 24
The bottom (horizontal) of the parallelogram is 6.4, the height is 5, and the side length of the slope is 5.6,
Its area is base * height = 6.4 * 5 = 32, its perimeter is the sum of four sides = 2 * (6.4 + 5.6) = 24
(as long as the length of the oblique side of the parallelogram is not less than the height, it is in accordance with)