If 1 / M-1 / N = 3, find the value of (2m-3mn-2n) / (m-2mn-n) (online, etc.)

If 1 / M-1 / N = 3, find the value of (2m-3mn-2n) / (m-2mn-n) (online, etc.)

1/m-1/n=3,
(2m-3mn-2n)/(m-2mn-n)
=(2/n-3-2/n)/(1/n-2-1/m)
=[2(1/n-1/n)-3]/(1/n-1/m-2)
=[2*3-3]/(3-2)
=3/1
=3

If 1 / M-1 / N = 3, find the value of (2m-3mn-2n) / (m-2mn-n)

1/m-1/n=3
(2m-3mn-2n)/(m-2mn-n)
Divide by Mn
=(2/n-3-2/m)/(1/n-2-1/m)
=[2*（-3)-3)/(-3-2)
=9/5

Simplify m-2mn-n into 2m-3mn-2n

(2m-3mn-2n)/(m-2mn-n)
=[2(m-2mn-n)+mn]/(m-2mn-n)
=2+mn/(m-2mn-n)

If 3mn-6n2 + 1 = 2mn-a, then a=______ ．

A = 2Mn - (3mn-6n2 + 1) = 2mn-3mn + 6n2-1 = - Mn + 6n2-1

Known parabola y = X2 - (M2 + 4) x-2m2-12
seek
1: When m is a real number, the chord length of X-section parabola is equal to 12
2: What is the minimum chord length when m is a real number

Let y = 0, then x ^ 2 - (m ^ 2 + 4) x-2m ^ 2-12 = 0 and (x1-x2) ^ 2 = (x1 + x2) ^ 2-4x1x2, where X1 + x2 = - B / a = m ^ 2 + 4, x1x2 = C / a = - 2 (m ^ 2 + 6) so (x1-x2) ^ 2 = (m ^ 2 + 4) ^ 2 + 8 (m ^ 2 + 6) let m ^ 2 = t, then (x1-x2) ^ 2 = (T + 4) ^ 2 + 8 (T + 6) (t ≥ 0) 1. The chord length of the x-axis section parabola is 12, then the equation

If the square roots of M are 2n-3 and n-12, then M =?

I'm glad to answer your question
The square roots of M are 2n-3 and n-12
∴2n-3=-(n-12)
2n-3+n-12=0
3n-15=0
n=5
m=(±7)^2=49

Let m, n be rational numbers, and m, n satisfy m ^ 2 + 2n + n √ 2 = 17-4 √ 2, find the square root of M + n

M & # 178; + 2n + n √ 2 = 17-4 √ 2 ᙽ m, n is a rational number, M & # 178; + 2n is also a rational number, n √ 2 is an irrational number, M & # 178; + 2n = 17, and N √ 2 = - 4 √ 2 gives m = ± 5, n = - 4. When m = - 5, n = - 4, M + n = - 5-4 = - 9, - 9 has no square root, M + n = 5-4 = 1 ? (± 1) & # 178; = 1 ᙩ m + n has a square root of ± 1

Find the square root of (m-2n + 3) (m-2n-3) + 9
Wait online

(m-2n+3)（m-2n-3)+9
=[(m-2n)+3][（m-2n)-3]+9
=(m-2n)^2-9+9
=(m-2n)^2
The square root of (m-2n + 3) (m-2n-3) + 9 is m-2n or 2n-m

What is the square root of (m-2n + 3) (m-2n-3)
Nine more

Your question should be: find the square root of (m-2n + 3) (m-2n-3) + 9
Find (m-2n + 3) (m-2n-3) + 9 first
Because from the square difference formula, (m-2n + 3) (m-2n-3) + 9 = [(m-2n) ^ 2-9] + 9 = (m-2n) ^ 2
So the square root of the original formula is ± (m-2n) ^ 2

How to solve the equations 2m + n = 8 2n-m = 1?

2m+n=8…… ① 2n-m=1…… ② 2 × 2, 4n-2m = 2 ③ 1 + 3 gives 5N = 10, n = 2. Substituting n value into 1 gives 2m + 2 = 8, the solution gives m = 3, so m = 3, n = 2 are the solutions of the original equations