3 (X-2) = 5 (2x + 3) 2 (0.3x-4) - 5 (0.2x + 3) = 9 / 2 X-7 = 5 + X process!

3 (X-2) = 5 (2x + 3) 2 (0.3x-4) - 5 (0.2x + 3) = 9 / 2 X-7 = 5 + X process!

3(x-2)=5(2x+3) -> 3x-6=10x+15 -> -7x=21 -> x=-3
2(0.3x-4)-5(0.2x+3)=9 -> 0.6x-8-x-15=9 -> -0.4x=32 -> x=-80
x/2-7=5+x -> x-14=10+2x -> x=-24

（5-3x）/3-1=（3-2x）/9-x
Solve the equation. Pay attention to the test
Inspection format:
Test: put x = Substitute into the left and right sides of the original equation
Left =
Right =
Left = right
∴x＝…… Is the solution of the original equation

1 general score: multiply left and right by 9 to get 3 (5-3x) - 9 = (3-2x) - 9x
2 remove brackets: 15-9x-9 = 3-2x-9x
The solution is 2x = - 3
x=-3/2
Test: substitute x = - 3 / 2 into the left and right sides of the original equation
Left = (5 + 3 * 3 / 2) - 1 = 13 / 6
Right = (3 + 2 * 3 / 2) / 9 - (- 3 / 2) = 13 / 6
Left = right
∴x＝…… Is the solution of the original equation

(0.8x + 0.9) / 0.5 = (x + 5) / 2 + (0.3x-0.2) / 0.3
（0.8x+0.9）/0.5=（x+5）/2+（0.3x-0.2）/0.3
Solving equations, using the method to denominator, to process, thank you

Take six on both sides
Then 12 (0.8x + 0.9) = 3 (x + 5) + 20 (0.3x-0.2)
9.6X+10.8=3X+15+6X-4
0.6X=0.2
X=1/3

(0.8x+0.9)÷0.5=(x+5)÷2+(0.3x-0.2)÷0.3
Using the method of removing the denominator to solve the equation,

(8x+9)÷5=(x+5)÷2+（3x-2)÷3
Multiply both sides by 30
6(8x+9)=15(x+5)+10(3x-2)
48x+54=15x+75+30x-20
3x=1
x=1/3

2.5 × 4 + 3x = 12.4, and 1.8x-3.5 × 0.2 = 2.9

Please write all nonnegative integer solutions that make (3x + 2) (3x-4) > 9 (X-2) (x + 3) hold______

The solution set of inequality (3x + 2) (3x-4) > 9 (X-2) (x + 3) is: x < 4615, so his nonnegative integer solutions are 0, 1, 2, 3

Please write all nonnegative integer solutions that make (3x + 2) (3x-4) > 9 (X-2) (x + 3) hold______

The solution set of inequality (3x + 2) (3x-4) > 9 (X-2) (x + 3) is: x < 4615, so his nonnegative integer solutions are 0, 1, 2, 3

Find out the non negative integer that makes (3x + 2) (3x-4) > 9 (X-2) (x + 3) hold

Only 0 holds

Non integer solutions of X + 3 ≤ 2 (5-3x)

X + 3 ≤ 2 (5-3x) non negative integer solution!
x+3≤10-6x
7x≤7
x≤1
x=0,1.

If (x + a) (x + b) = x ^ 2 + 3x + 2 holds, where a and B are integers, then what is a + B

（x+a）（x+b）
=x²+(a+b)x+ab
=x²+3x+2
So a + B = 3, ab = 2
a+b=3