Find the solution of the equation: five times of a number is 4.7 greater than 9.8, what is the number?

x*5-9.8=4.7
5*x=14.5
x=2.9

Two times of a number is 9.6 less than 100. To find this number, (calculate by equations)

Let this number be X
Then 2x = 100-9.6
2x=90.4
x=90.4÷2=45.2
A: that's 45.2

It is known that the linear equations of two sides of a parallelogram are x + Y-1 = 0 and 3x-y-5 = 0 respectively, and the intersection of its diagonals is m (3,3),
Find the linear equation of the other two sides of the parallelogram

Let ad equation: x + Y-1 = 0, CD equation: 3x-y-5 = 0, get intersection D (3 / 2, - 1 / 2) from x + Y-1 = 0 and 3x-y-5 = 0, its symmetry point B (9 / 2,13 / 2) BC / / ad about M (3,3), BC line slope = - 1, passing B (9 / 2,13 / 2), so BC equation is: y = 11 Xba / / CD, BC line slope = 3, passing B (9 / 2,13

When x = 2, y = 1, x = 3, y = 3, x = 4, y = 6, x = 5, y = 10, x = 6, y = 15, find: y = () x; or the equation between Y and X

y=x(x-1)/2 （x>=2）

Given that equation 3x equals 5x-8 and equation 2 / 1y equals - 2, how much x + y = please explain in detail

3x=5x-8
x=4
y/2=-2
y=-4
So x + y = 4-4 = 0

If | 3x-9 | + | 2 / 1y + 1 | = 0, the equation 3 / 1x-2 / 1y = Z + 5 / 6 is obtained

|3x-9 | ≥ 0, | 2 / 1y + 1 | ≥ 0, if the sum of the two is equal to 0, only each term is 0
So x = 3, y = - 2
The substitution equation is 2 = Z + 5 / 6
Z=7/6

Find the tangent equation of the circle passing through a point a (6,8) on the circle (x-3) + (y-4) = 25. The answer is 3x + 4y-50 = 0,

The coordinates of the center of the circle are o (3,4)
The slope of OA is k = (8-4) / (6-3) = 4 / 3
Then the slope of tangent K '= - 1 / (3 / 4) = - 3 / 4
So, the tangent equation is Y-8 = - 3 / 4 (X-6)
That is 3x + 4y-50 = 0

The tangent equation passing through a point (0,1) on the curve y = e ^ - 6x is?

y=e^(-6x)
y'=-6e^(-6x)
Then the tangent slope at point (0,1) is y '| x = 0 = - 6
The linear equation is y = - 6x + 1

Tangent equation of curve y = x ^ 3-6x + 1 at point (1, - 1)

The derivative of the curve is
y'=3x^2-6
Substitute x = 1 to get
y'=-3
Let the tangent equation of curve y = x ^ 3-6x + 1 at point (1, - 1) be
Y = - 3x + B, then
-1 = - 3 + B, so B = 2
So the curve equation is
y=-3x+2

Equation: √ {(x-4) ^ 2 + y ^ 2} - the curve equation represented by {(x + 4) ^ 2 + y ^ 2} = 6 is——
Why do we need x ≤ - 3 to solve hyperbolic equation?

The distance between a point and (4,0) is {(x-4) ^ 2 + y ^ 2} {(x + 4) ^ 2 + y ^ 2} is the distance between a point and (- 4,0). The difference between the distance between a point and (4,0) and that between a point and (- 4,0) is 6

Find the solution of the equation: five times of a number is 4.7 greater than 9.8, what is the number?