The sum of 5 times of a number and 30 is 40. Find the number. Solve the equation

The sum of 5 times of a number and 30 is 40. Find the number. Solve the equation

Let this number be X
According to the equation: 5x + 30 = 40
X=（40-30）/5=2
This number is 2

If X-1 = 3x + B has infinitely more than one solution, find the value of A-1 / b
I'm sorry, it should be that if the equation AX / 2-1 = 3x + B about X has infinitely more than one solution, find the value of A-1 / b.

You don't write it clearly. Is it ax / 2-1 or (AX-1) / 2
If ax / 2-1, then
ax/2-1=3x+b
(a/2-3)x=b+1
So when a / 2-3 = B + 1 = 0, the equation has infinitely many solutions
a=6,b=-1
a-1/b=6-1/(-1)=7
If (AX-1) / 2, then
(ax-1)/2=3x+b
(a-6)x=2b+1
So when a-6 = 2B + 1 = 0, the equation has infinitely many solutions
a=6,b=-1/2
a-1/b=6-1/(-1/2)=8

If there are infinitely many solutions to the equation x 2 / 2 minus 1 = 3x + B, find a minus 1 / b

Double two on both sides
ax-1=6x+2b
(a-6)x=2b+1
If there are infinitely many solutions, then a-6 = 0, 2b + 1 = 0
a=6,b=-1/2
So A-1 / b
=6+2
=8

How to solve the equation that 3 minus 2 / x minus 1 equals 3x minus 1

3-(x-1)/2=3x-1
6-(x-1)=2(3x-1)
6-x+1=6x-2
7-x=6x-2
6x+x=7+2
7x=9
x=9/7