Solution equation: (1 + x) (2 + x) (3 + x) (4 + x) = 120

Solution equation: (1 + x) (2 + x) (3 + x) (4 + x) = 120

(1 + x) (2 + x) (3 + x) (4 + x) = 120 (1 + x) (4 + x) (3 + x) (2 + x) = 120 (X & # 178; + 5x + 4) (X & # 178; + 5x + 6) = 120, let X & # 178; + 5x + 4 = y, then y (y + 2) = 120Y & # 178; + 2y-120 = 0 (Y-10) (y + 12) = 0, then y = 10 or y = - 12, so x & # 178; + 5x + 4 = 10 or X & # 178; + 5x + 4 = - 12x & # 178; + 5

The solution of the equation x (x + 1) (x + 2) (x + 3) = 120 has two roots

x(x+1)(x+2)(x+3)=120﹙x²＋3x﹚﹙x²＋3x＋2﹚－120＝0﹙x²＋3x﹚²＋2﹙x²＋3x﹚－120＝0﹙x²＋3x＋12﹚﹙x²＋3x－10﹚＝0∵ x²＋3x＋12＝﹙x＋3/2﹚²＋39/4≠0∴ x&#...