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When k, the solution of equation 5x-2k = - x + 4 is between 1 and 3
5x-2k=-x+4
6x=4+2k
x=(4+2k)/6
1＜(4+2k)/6＜3
6＜4+2k＜18
2＜2k＜14
1＜k＜7
K is an integer, so that the solution of the equation (K-6) + 1 = 2K + 2-5x about X is an integer, and the value of K is obtained
k-5=2k+2-5x
-k-7=-5x
5x=k+7
X = 5 / K + 7
K + 7 is a multiple of 5
k=-2、3、8.
When k is in what range, the solution of the equation 5x-2k = - x + 4 is between 1 and 3, including 1 and 3
5x-2k=-x+4
6x=4+2k
x=(2+k)/3
Because 1 ≤ x ≤ 3
So 1 ≤ (2 + k) / 3 ≤ 3
3≤2+k≤9
1≤k≤7
So when 1 ≤ K ≤ 7, the solution of the equation 5x-2k = - x + 4 is between 1 and 3
This is the original answer '` no plagiarism ~!
When k is what number, the equation 5x-6 = 3 (x + k) (1) is a positive number (2) is a negative number (3) is greater than k
When k is what number, the equation 5x-6 = 3 (x + k)
5x-6＝3x+3k
2x=6+3k x=(6+3k)/2
When k is what number, the equation 5x-6 = 3 (x + k) (1) is a positive number 3K + 6 > 0 K > - 2
(2) It is negative 3K + 6-6
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