Let p be on the x-axis, Q be on the y-axis, m (- 1,2) be the midpoint of the segment PQ, / PQ / be equal to

Let p be on the x-axis, Q be on the y-axis, m (- 1,2) be the midpoint of the segment PQ, / PQ / be equal to

Let P (x, 0); Q (0, y)
(x + 0) / 2 = - 1, so x = - 2
(0 + y) / 2 = 2, so y = 4
So, P (- 2,0); Q (0,4)
Therefore, PQ = √ (4 + 16) = √ 20 = 2 √ 5

The line L: X-Y + B = 0 intersects with the coordinate axis at P and Q. if the absolute value PQ is equal to two, find the midpoint coordinate of PQ. Why choose B and let Q be (- b.0) p be (0. B)

If the line L: X-Y + B = 0 intersects the coordinate axis at P (- B, 0), q (0, b), then
|PQ|=|b|√2=2,
Ψ B = soil √ 2,
The midpoint m of PQ is (- B / 2, B / 2) = (√ 2 / 2, √ 2 / 2), or (√ 2 / 2, √ 2 / 2)

Let p be on the x-axis, Q be on the y-axis, and the midpoint of PQ be m (- 1,2), then what is the length of PQ
What does bornagainer's answer mean?

Radical (2 * 2 + 4 * 4) = 2 radical 5
Because it's the midpoint, P is (- 2,0), q is (0,4)
Then there is the formula of distance between two points

Given p (1, y), q (x, 2), if PQ / / X axis and line segment PQ = 3, then x =. Y =

If PQ / / X axis
Then KPQ = (Y-2) / (1-x) = 0
That is Y-2 = 0, y = 2
PQ=3
|x-1|=3
X = 4 or - 2