Given that m and N are symmetric with respect to y axis, and point m is on hyperbola y = 12x, and point n is on straight line y = x + 3, if the coordinates of point m are (a, b), then the vertex coordinates of parabola y = - abx2 + (a + B) x are (a, b)______ ．

Given that m and N are symmetric with respect to y axis, and point m is on hyperbola y = 12x, and point n is on straight line y = x + 3, if the coordinates of point m are (a, b), then the vertex coordinates of parabola y = - abx2 + (a + B) x are (a, b)______ ．

∵ m, n about Y-axis symmetric point, the ordinate is the same, the abscissa is opposite to each other ∵ m coordinate is (a, b), n coordinate is (- A, b), ∵ B = 12a, ab = 12; b = - A + 3, a + B = 3, then the abscissa of parabola y = - abx2 + (a + b) x = - 12x2 + 3x is x = − a + B − 2Ab = 31 = 3; ordinate is 0 − (a

Given that m and N are symmetric with respect to y axis, and that M is on hyperbola y = 12x and N is on straight line y = x + 3, let the coordinates of symmetric points of M be (a, b), then the quadratic function y = - abx2 + (a + b) x has the most significant______ Value, yes______ ．

The coordinates of point m are (a, b), and the coordinates of point n are (- A, b). Point m is on the image of inverse scale function y = 12x, and point n is on the image of primary function y = x + 3. AB = 12a + B = 3, so the quadratic function y = - abx2 + (a + b) x is y = - 1

Given a = 2013, B = 1 / 2013, find ((a Λ 2 / a-b) - (B Λ 2 / B-A)) / (a + B / AB)

The molecule can be combined into a ^ 2 / A-B ^ 2 / B + A-B = (b * a ^ 2 + A * B ^ 2) / AB + A-B, ab = 1 can be reduced to ab (a + b) + A-B = 2A
A * b = 1, the denominator is a + B
The fraction can be combined into 2A / (a + b) =

Given / x + 1 / = - [Y-1] ^ 2, find the value of x ^ 2012 + y ^ 2013

That is / x + 1 / + [Y-1] ^ 2 = 0
So x + 1 = Y-1 = 0
x=-1,y=1
So the original formula = (- 1) ^ 2012 + 1 ^ 2013
=1+1
=2

Y = √ X-1 = √ 1-x, find the 2013 power of X + the Y power of 2013
Wrong question, y = √ X-1 + √ 1-x

y=√x-1=√1-x
So √ X-1 = √ 1-x, both sides are the same square
x-1=1-x,
x=1,y=0
So x to the power of 2013 + 2013 to the power of y = 1 + 1 = 2

Given that a and B are opposite numbers, and | X-2 | + | y | = 0, find the value of Y - (a + B + CD) x + (a + b) to the power of 2013 and the power of (CD) to the power of 2013

Given that a, B are opposite numbers, CD are reciprocal numbers, and | X-2 | + | y | = 0, find the value of the power of 2013 of Y - (a + B + CD) x + (a + b) and the power of 2013 of - (CD) of X to the second power of Y - (a + B + CD) x + (a + b). A, B are opposite numbers, CD are reciprocal numbers, and | X-2 | + | y | = 0 | a + B = 0, CD = 1 x = 2, y = 0 | x to the second power of Y - (a + B + CD) x + (a + b) and the power of 2013 of - (C

A mathematical problem: 3a-2b = 3b-2a + 1, the following statement is correct: A: A is greater than B B: A is less than B C: A is equal to B. D: can't compare

A

3a-2a equals a or 1

3a-2a equals a
In the top right corner of my answer, click comment, and then you can choose satisfied, the problem has been solved perfectly

On the coordinate characteristics of x-axis symmetric points and y-axis symmetric points

With regard to the coordinate characteristics of x-axis symmetric points, the abscissa does not change and the ordinate is opposite to each other
On the coordinate characteristics of y-axis symmetric points, the ordinate is constant, and the abscissa is opposite to each other

X on the x-axis_ y_ X on the y-axis_ y_ X at the origin_ y_ On the coordinate characteristics of x-axis symmetric points () on the coordinate characteristics of y-axis symmetric points ()

X = 0 on x-axis, x = 0 on y-axis, x = 0 on origin, x = y = 0 on X-axis
On the coordinate characteristics of y-axis symmetric points: the vertical axis does not change and the horizontal axis becomes the opposite number