The equation of the line L which is parallel to the line 3x + 4Y + 1 = 0 and whose intercept sum on the two axes is 73 is______ .

The equation of the line L which is parallel to the line 3x + 4Y + 1 = 0 and whose intercept sum on the two axes is 73 is______ .


The slope of line 3x + 4Y + 1 = 0 is - 34 ∵ two lines are parallel ∵ the slope of line L is - 34. Let the equation of line l be XA + Yb = 1, then the slope k = - BA = − 34 & nbsp; is 73 ∵ a + B = 73 & nbsp; the sum of intercept on two coordinate axes is 73 ∵ a + B = 73 & nbsp; the answer is: 3x + 4y-4 = 0



The equation of the line L which is parallel to the line 3x + 4Y + 12 = 0 and the area of the triangle formed with the coordinate axis is 24 is______ .


Analysis: let the equation of line l be 3x + 4Y = a (a ≠ 0), then the intersection points of line L and two coordinate axes are (A3, 0), (0, A4), 〈 12 × | A3 | · | A4 | = 24, the solution is a = ± 24, and the equation of line L is 3x + 4Y = ± 24. So the answer is: 3x + 4Y + 24 = 0 or 3x + 4y-24 = 0



When a is the sum, the line (A-1) x + (3-A) y + a = 0. The intercept on the two axes is equal
Process
Thank you


(a-1)x+(3-a)y+a=0
Equal intercept: - A / (A-1) = - A / (3-A),
The solution is a = 2



A line passing through point a (1,2) and having equal absolute values of intercept on two coordinate axes______ .


A straight line passing through point a (1,2) and having equal absolute values of intercept on two coordinate axes: when the intercept is 0, the straight line passes through the origin: y = 2x; when the slope is 1, the linear equation: X-Y + 1 = 0; when the slope is - 1, the linear equation: x + Y-3 = 0. So the answer is: y = 2x or x + Y-3 = 0 or X-Y + 1 = 0



Given the point a (1, a), the circle x ^ 2 + y ^ 2 = 4. If the chord length of a straight line passing through point a with equal intercept on two coordinate axes is 2 √ 3, find the value of A


When the slope is 1 or - 1, the linear equation is Y-A = X-1, that is, y = x + A-1 and x ^ 2 + y ^ 2 = 4 are simultaneous, and the chord length formula is 2x ^ 2-2 (A-1) x + (A-1) ^ 2-4 = 0 = (k ^ 2 + 1). (x1-x2) absolute value = 2. √ [(x1 + x2) ^ 2-4x1x2] = 2. √ [8 - (a -...]



How many lines passing through a (- 1,2) with equal intercept on two coordinate axes?
I think it's three, one intercept is positive, one intercept is negative, one intercept is 0, but why is the answer two?


Do you use intercept?
(x / a) + (Y / b) = 1, because the intercept is equal, so a = B, so there is (x + y) / a = 1, substituting point a into a = b = 1, the equation is x + y = 1
Then, let y = KX and point a be substituted to get another equation y = - 2x
Or is there another way
Let y = KX + B, let x = 0, y = B (this is the longitudinal intercept), and then y = 0, x = - B / K (this is the transverse intercept), because the intercept wants to wait, so B = - B / K
The discussion can be divided into two cases: (1) if B ≠ 0, B can be eliminated and K = - 1 can be obtained. Substituting point a into the equation y = KX + B, 2 = - 1 * (- 1) + B can be obtained, so B = 1, so the equation is x + y = 1
② B = 0, substituting point a into the equation y = KX + B, we get 2 = - 1K, k = - 2, and another equation y = - 2x
In my opinion, if the two intercepts are both negative, after they are equal, the negative sign can be eliminated at the same time, then the two positive intercepts are still equal
So there are only two equations
If you still don't understand, I suggest you ask the teacher. The teacher is authoritative, and you can understand it easily



How to solve the linear equation which passes through point a (- 3,2) and has equal intercept on two coordinate axes?
Why is y = - 2 / 3x when crossing the origin?


1) When passing through the origin, y = - 2 / 3x
2) Let X / A + Y / a = 1 without passing through the origin, and substitute a (- 3,2) into a = - 1



1. The equation of the straight line which passes through the point P (2,3) and whose absolute value of intercept on two coordinate axes is equal
2. Solve the equation of a line passing through point P (2,3) and whose intercept on x-axis is twice that on y-axis
emergency


Question 1: (1) when the intercept is 0, that is, the case of crossing the origin, it is obvious that the linear equation is y = 3x / 2 (2) when the intercept is not 0, according to the intercept formula: X / A + Y / b = 1, we can set the linear equation as x + y = a, and substitute the point P (2,3) to get a = x + y = 2 + 3 = 5, so the linear equation is x + y = 5



Find the linear equation of point P (- 2, - 3) with equal intercept on two coordinate axes


The first case
If the intercept is equal, let the equation be x / A + Y / a = 1
Substituting (- 2, - 3) into - 3 / A-2 / a = 1
a=-5
Equation x / (- 5) + Y / (- 5) = 1
x+y+5=0
In the second case, crossing the origin (intercept is 0)
The equation is y = 3 / 2x
3x-2y=0



The equation of a straight line passing through point (2, 3) with equal absolute values of intercept on two coordinate axes is______ .


① If the line passes through the origin, the slope k = 32, and the required equation of the line is 3x-2y = 0. ② when the line does not pass through the origin, the equation of the line is x ± y = a, and (2,3) is substituted into the equation of the line to get 2 ± 3 = a, and the solution is a = 5 or - 1. The equation of the line is x + Y-5 = 0, X-Y + 1 = 0