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If the intercept of a ^ x-6y-12a = 0 (a ≠ 0) on the X axis is twice that on the Y axis, what is a
Let y = 0, then a ^ x = 12a, that is, x = loga (12a) = (loga 12) + 1 (a is the base)
So the intercept on the x-axis is (loga 12) + 1
Let x = 0, then 6y = 1-12a, that is, y = (1-12a) / 6
So the intercept on the y-axis is (1-12a) / 6
According to the meaning of the title, (loga 12) + 1 = (1-12a) / 3
The solution is a = 1 / 12
The equation x / (Y-2) = 1 represents a line with a slope of 1 and an intercept of 2 on the y-axis
What's wrong?
Wrong! When you move Y-2 to the left of the equation, you ignore a condition, that is, Y-1 ≠ 0. So the description is wrong!
The slope is - 2, the intercept on the Y axis is - 1, write the linear equation
The slope is - 2, that is k = - 2
The intercept on the Y axis is - 1, that is, B = - 1
So y = - 2x-1
The linear equation with a slope of 3 and an intercept of 2 on the y-axis is?
Let the equation be y = KX + B
Because the slope is 3, so k = 3
And the intercept on y is 2,
So the equation goes through (0,2)
That is, B = 2
So the equation is
y=3x+2
Change to the general form
3x-y+2=0
The slope is 2. The intercept on the Y axis is 3
y=2x+3
The intercept formula of linear equation is (x / - 5) + (Y / 2) = 1, which is transformed into equation - 2x + 5y-10 = 0
The intercept formula of the linear equation is (x / - 5) + (Y / 2) = 1. I multiply each term by 10 at the same time, that is to say, the equation - 2x + 5y-10 = 0. But the positive solution is 2x-5y + 10 = 0. I'm studying by myself, and ask the master to point out whether the two equations are the same. Why do I choose the latter for the positive solution?
Because in general, for the convenience of teachers, there are standard answers, so in the binary linear equation, as you have given, before x is generalized as a positive number, if it is a point oblique type, intercept type, according to the actual discussion
What is the linear equation with slope 2 and longitudinal intercept 1?
RT.
Why not y = 2x ± 1
Intercept 1 is
y=2x+1
Intercept is - 1
y=2x-1
The intercept is positive or negative
Given that the equation of oblique longitudinal section of a line is y = - 2x + 3, then what is the slope of the line k = and what is the longitudinal intercept?
The same formula and answer
k=-2,b=3
Slope and intercept of 2x + 1 = 0
There is no slope and no longitudinal intercept
Find the linear equation with slope 3 and longitudinal intercept - 4
Let y = KX + B
If k = 3, then y = 3x + B
Take (x, y) = (0, - 4) to get b = - 4
So y = 3x-4
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