If the image of the first-order function y = 2mx + (m-2) passes through the coordinate origin, its analytical expression is ()

Passing through the coordinate origin
Then m-2 = 0
m=2
Its analytical expression is (y = 4x)
)

Given the inverse scale function y = k - 1 / x, the image is located in the first and third quadrant respectively
(1) Find the range of K;
(2) If there is an intersection point between the image of a linear function y = 2x + 3 and the image of the inverse scale function, the ordinate is 4
① Find the value of inverse proportional function y when x = - 6;
② When 0 ﹤ x ﹤ 1 / 2, the value range of the primary function y is obtained

(1) ∵ the two branches of the inverse scale function y = k-1 / X are located in the first and third quadrants respectively. ∵ k-1 > 0 ∵ k > 1 (2) let the intersection coordinates be (a, 4), and substituting them into the analytic expressions of the two functions, the solution of k-1 / A = 4 (1) 2A + k = 4 (2) is a = 0.5, k = 3 ∵ the analytic expression of the inverse scale function is y = 2 / X (1) when x = - 6, the inverse scale function ∵

If the image of the first-order function y = 2mx + (m-2) passes through the coordinate origin, its analytical formula is-------
a:y=-2
b:y=4x
c: Y = - 2 or y = 4x
d: Not sure

If the images of the first-order function y = 2x and the inverse scale function y = 2 x all pass through points a and B, point a is known to be in the third quadrant;
(1) Find the coordinates of points a and B;
(2) If the coordinate of point C is (3,0), and the quadrilateral with points a, B, C and D as its vertex is a parallelogram, please write the coordinate of point D;
(3) If the coordinate of point C is (T, 0), t > 0, the quadrilateral ABCD is a parallelogram. When t is, point D is in y
On axis
I can do both the first and second questions,

The continuous equation y = 2x, y = 2, x, (xy = 2), in fact, this form is more beautiful. We get 2x & # 178; = 2, X & # 178; = 1, x = ± 1. We get two solutions, x = 1, y = 2,; X = - 1, y = - 2. A is in three quadrants, a (- 1, - 2), B (1,2), D (- 3,0). If we want to process, we use the formula of calculating distance. The distance of AB point is equal to (x1-x2) &# 178

It is known that the image of a certain function is parallel to the straight line y = 3 / 2x-2, and the abscissa of the intersection point with the X axis is - 2. Try to find the analytic expression of this function and explain it
Try to find the analytic expression of this function and explain how the image can be obtained by the transformation of the line y = 3 / 2x - 2

Let y = 2 / 3x + B (parallel, K is the same)
Substituting (- 2,0) into
0=-3+b
b=3
｜ y = 3x + 3 of 2

Y = KX + B function, when k > 0, the larger K is, how does the function change? Is it closer to X axis or Y axis? When k < 0?
Get extra points as soon as possible

When k > 0, the larger the K is, the closer it is to the y-axis (tends to be vertical)
K < 0, the larger the K is, the closer to the x-axis (tends to be horizontal)

The concept of quadratic function in elementary school?

The basic definition of Y has the following relations about the linear function of the independent variable X: 1. Y = KX + B (k is any non-zero constant, B is any constant). When x takes a value, y has and only has one value corresponding to X. if there are two or more values corresponding to x, it is not a linear function

If the point (2a, - a) is on the function image of function y = KX, then K=

If the point (2a, - a) is on the function image of function y = kx
Then - a = 2A * k
So k = - 1 / 2

What is the intercept expression in the analytic expression of a function?,

The intercept formula A is the intercept of the x-axis, which cannot be equal to the distance. The distance must not be negative, but the intercept can be positive or negative. For example: X / (- 2) + Y / 4 = 1, the intercept on the x-axis is - 2, the intercept on the Y-axis is 4, but the distance from the intersection of the x-axis to the origin is 2, not - 2, and the distance from the intersection of the y-axis to the origin is 4

Given the sequence {an} {BN}, the point m (1,2) an (2, an), BN ((n-1) / N, 2 / N) is a positive integer for N, and m, an, BN are on the same line, find the general term {an}
Known sequence {an} {BN}, point m (1,2) an (2, an), BN ((n-1) / N, 2 / N)
If n is a positive integer, m, an and BN are on the same line, find the {an} general term

Using m, an, BN three points collinear:
Vector man (1, An-2), vector MBN (- 1 / N, 2 / N - 2), from the collinear condition, we get man / / MBN, that is (- 1 / N) (An-2) = 2 / N - 2, and the solution is an = 2n
Or from the slope of the straight line man and the slope of the straight line MBN are equal, the solution is almost the same

If the image of the first-order function y = 2mx + (m-2) passes through the coordinate origin, its analytical expression is ()