If the equation of the line L is y-m = (m-1) (x + 1), and the intercept of L on the Y axis is 7, then the real number M=

Let x = 0 and y = 7 be substituted to find the value of M
7-m=m-1
2m=8
m=4

Let the first n terms of the sequence {an} and Sn = N2, and the sequence {BN} satisfy BN = Anan + m (m ∈ n ) (I) if B1, B2, B8 are equal ratio sequences, try to find the value of M; (II) whether there is m, so that there is a certain term BT in the sequence {BN}, and B1, B4, BT (t ∈ n , t ≥ 5) are equal difference sequences? If yes, please indicate the number of m in line with the meaning of the question; if not, please explain the reason

(I) because Sn = N2, when n ≥ 2 & nbsp;, an = sn-sn-1 = 2N-1 & nbsp When n = 1 & nbsp;, A1 = S1 = 1, so an = 2N-1 & nbsp; (n ∈ n * & nbsp;) (4 points) so BN = 2n − 12n − 1 + M & nbsp; then B1 = 11 + m, B2 = 33 + m, B8 = 1515 + M & nbsp; from B22 = b1b8, we get (33 + m) 2 = 11 + m × 1515 + M & nbsp; solution M = 0 & nbsp; (rounding) or M = 9 & nbsp; so m = 9 & nbsp (7 points) (II) suppose that there is M & nbsp; such that B1, B4, BT (t ∈ n *, t ≥ 5) become an arithmetic sequence, that is, 2B4 = B1 + Bt, then 2 × 77 + M = 11 + m + 2T − 12t − 1 + M & nbsp; is reduced to t = 7 + 36m − 5 & nbsp (12 points) so when m-5 = 1, 2, 3, 4, 6, 9, 12, 18, 36 & nbsp; respectively, there are t = 43, 25, 19, 16, 13, 11, 10, 9, 8 & nbsp; suitable for the topic meaning, that is, there are such m, and there are 9 M & nbsp; suitable for the topic meaning (14 points)

If the intercept of the line (M + 2) x + (2-m) y = 2m on the X axis is 3, then the value of M is______ ．

Let x = 2 mm + 2 of y = 0, the intercept of (M + 2) x + (2-m) y = 2m on the x-axis be 2 mm + 2, and the intercept of (M + 2) x + (2-m) y = 2m on the x-axis be 3, the solution is m = - 6, so the answer is - 6

It is known that the sum of the first n terms of the sequence {an} is Sn, and the slope of the line passing through P (n, Sn) and Q (n + 1, sn-1) (n belongs to n) is 3n-2
Given that the sum of the first n terms of the sequence {an} is Sn, the slope of the straight line passing through P (n, Sn) and Q (n + 1, s (n-1)) (n belongs to n) is 3n-2, then the value of A2 + A4 + A5 + A9 is equal to?

[S（n-1）-Sn]/(n+1-n)=-an=3n-2
an=2-3n
a2+a4+a5+a9=4a5=-52

If the intercept of the line (M + 2) x + (2-m) y = 2m on the X axis is 3, then the value of M is ()
A. 65B. -65C. 6D. -6

∵ the intercept of the straight line (M + 2) x + (2-m) y = 2m on the x-axis is 3, ∵ if the straight line passes (3, 0), substituting it, we can get 3 (M + 2) = 2m, and the solution is m = - 6

Given that the sum of the first n terms of the sequence {an} is Sn, the slope of the straight line passing through P (n, Sn) and Q (n + 1, Sn + 1) & nbsp; (n ∈ n *) is 3n-2, then the value of A2 + A4 + A5 + A9 is equal to ()
A. 52B. 40C. 26D. 20

Given that the sum of the first n terms of the sequence {an} is Sn, the slope of the straight line passing through P (n, Sn) and Q (n + 1, Sn + 1) & nbsp; (n ∈ n *) is 3n-2, then: Sn + 1 − Sn (n + 1) − n = an + 1 = 3N − 2  an = 3n-5a2 + A4 + A5 + A9 = 40

If the intercept of the line (M + 1) x + (m2-m-2) y = m + 1 on the Y axis is equal to 1, then the value of the real number m is______ ．

It can be seen from the meaning of the question that if a straight line passes (0, 1), then m2-m-2 = m + 1 can be obtained by substituting, m2-2m-3 = 0 can be obtained by deformation, and M = 3 can be obtained by solution, or M = - 1 when m = - 1, m + 1 = m2-m-2 = 0, which does not meet the meaning of the question, so the answer is: 3

It is known that the sum of the first n terms of the sequence {an} is Sn, and Sn = 2an-2; the first term of the sequence {BN} is 1, and the point P (n, BN) is on the same straight line L (above n ∈ n *). Find: (1) the general formula of the sequence {an}, {BN}; (2) the sum of the first n terms of the sequence {ABN}, {ban}

(1) When n = 1, A1 = S1 = 2a1-2 ｜ A1 = 2, when n ≥ 2, an = sn-sn-1 = 2an-2 - (2an-1-2) = 2an-2an-1 ｜ an = 2an-1} {an} is an equal ratio sequence with 2 as the first term and 2 as the common ratio, that is, an = 2n

The inclination angle of the straight line L is 45 & # 186;, the intercept on the x-axis is - 2, the straight line L and the x-axis intersect at the points a and B respectively, and the line AB is taken as the edge to make the equilateral △ ABC. If there is a point P (M, 1) in the second quadrant to make the areas of △ ABP and △ ABC equal, the value of M can be obtained?

If the inclination angle is 45 & # 186;, then the slope of the line L where AB is located is k = 1, and the intercept on the X axis is - 2, then Y-2 = x, that is, X-Y + 2 = 0, so the coordinates of points a and B are (0,2), (- 2,0), that is, | OA | = | ob | = 2. According to the Pythagorean theorem, ab = 2 √ 2 and ABC is an equilateral triangle, so the height h = AB * sin60 ° = √ 6

The general term formula of sequence {an} is an = 1 / (√ n + √ (n + 1)) (n ∈ n *). If the sum of the first n terms is 10, then the number of terms is n

n=120
In each term, the 1 above an is divided into (√ (n + 1) + √ n) * (√ (n + 1) - √ n)
then...
Do you understand?

If the equation of the line L is y-m = (m-1) (x + 1), and the intercept of L on the Y axis is 7, then the real number M=