The distance between the image of the first-order function y = kx-3 and the intersection of x-axis and y-axis is 5 The graph of the function passes through the point (1, - 1) and is parallel to the line 2x + y = 5

The distance between the image of the first-order function y = kx-3 and the intersection of x-axis and y-axis is 5 The graph of the function passes through the point (1, - 1) and is parallel to the line 2x + y = 5

From Pythagorean theorem
The point of intersection with X axis is
(4,0) or (- 4,0)
4k-3=0 k=3/4 y=3x/4-3
-4k-3=0 k=-3/4 y=-3x/4-3
k=-2
-2+b=-1
b=1
y=-2x+1

When the image of function y = KX (K ≠ 0) passes through point a (- 2 / 3,6), write out the analytic formula of the function and explain which quadrants the function image passes through?

Point a (- 2 / 3,6) is substituted
6=-2/3*k
k=-9
y=-9x
The image goes through two or four quadrants

If the image of a function y = KX + 3 passes through point a, the distance from the point to the x-axis is 2, and the distance to the y-axis is 1, try to find the analytic expression of this function

∵ the distance from point a to X axis is 2, the distance from point a to y axis is 1, and the coordinates of point a are (1,2) or (- 1,2) or (- 1, - 2) or (1, - 2). When the coordinates of point a are (1,2), K + 3 = 2, the solution is k = - 1, and the analytic expression of the first-order function is y = - x + 3; when the coordinates of point a are (- 1,2), - K + 3 = 2, the solution is k = 1

If the image of the function y = - KX passes through the first three quadrants, then the quadrant that the image of y = KX + 1 does not pass through is

The image of function y = - KX passes through the first three quadrants, so k > 0
The image of y = KX + 1 passes through the first, second and fourth quadrants, and does not pass through the third quadrant

If the image of a linear function y = KX + B passes through (- 2, - 1) and points (1,2), then the image of this function does not pass through the quadrant

Think about the fourth quadrant. Imagine

If the image of function y = KX does not pass through the second quadrant, then the condition that K should satisfy is

Because it does not pass through the second quadrant, K is greater than 0, but B may be equal to 0, so K is greater than or equal to 0

Given that the image of the function y = KX passes through the point (2,3), then the image of y = kx-1 must not pass through the quadrant

But the second quadrant
K = 2 / 3 when k > 0 and B < 0, the image passes through the first three or four quadrants, but the second quadrant

If the image of a function y = KX + 5 passes through a point (- 1,2), then K=____ The image does not go through the second step____ Quadrant,

Substituting point (- 1,2) into equation
2=k*(-1)+5
k=5-2=3
So y = 3x + 5 is just four quadrants

If the image of function y = KX passes through the second and fourth quadrants, then the image of function y = - kx-2 does not pass through the second quadrant___ quadrant

Because the image of the function y = KX passes through the second and fourth quadrants,
So K0,
Then the image of the function y = - kx-2 passes through one, three, four and does not pass through the second quadrant

Given that the image of a function y = - kx-1 does not pass through the second quadrant, then the image of function y = KX must pass through the third quadrant

The fourth quadrant passes the point (0, - 1)