A linear equation () This is a multiple choice question A：2x+y-12=0 B: 2X + Y-12 = 0 or 2x-5y = 0 C: X + 2y-9 = 0 or 2x-5y = 0 D: X + 2y-9 = 0 or 2x + 5Y = 0 Requirement: not only options

"The intercept on the x-axis is twice the intercept on the y-axis" (1) if the intercept is not 0, that is, the slope of the equation is equal to - 1 / 2, passing through the first quadrant or the fourth quadrant (because the intercept is signed), and the point (5,2) passing through the first quadrant, only one line should conform to the condition, substituting the point (5,2), Y-2 = - (X-5

If a straight line passes through a point P (5,6), its intercept on the x-axis is twice that on the y-axis, then the equation of the straight line is______ ．

(1) When the line passes through the origin, the intercept of the line on the x-axis and the intercept on the y-axis are equal to 0, which is obviously true, so the slope of the line is 65 and it passes through the origin, so the analytical formula of the line is y = 65x, which is reduced to 6x-5y = 0; (2) when the line does not pass through the origin, the intercept on the x-axis is twice that on the y-axis

The equation of a straight line passing through a point (5,2) whose intercept on the x-axis is twice that on the y-axis is

Suppose that the linear equation is y = ax + B
If a line passes through a point (5,2), then 2 = 5A + B
The intercept on the x-axis is the value of X when y = 0, that is (- B / a), and the intercept on the y-axis is B
B / a = 2B
The solution of the two equations is a = - 0.5, B = 4.5
y=-1/2x+9/2
Both intercepts are 0, and the equation is y = (2 / 5) X

The equation of line L passing through point P (- 3, - 4) with equal intercept on x-axis and y-axis

Let the slope of the line l be K
The equation y + 4 = K (x + 3) of line L
x=0 y=3k-4
y=0 x=4/k-3
Equal intercept
3k-4=4/k-3
The solution is k = - 1 or K = 4 / 3
The equation x + y = - 7 or y = 4 / 3 * x of line L

If the line L passes through the point a (- 5, - 3) and the intercept on the X and Y axes is equal, the equation of l can be solved (linear equation solution)

Let the linear equation y = KX + B, when x = 0, y = B, when y = 0, x = - B / K, so B = - B / K, and because the line L passes through point a (- 5, - 3), so - 5K + B = - 3, so k = 3 / 5, B = 0 or K = - 1, B = - 8, so the equation of L is y = 3x / 5 or y = - X - 8

The equation of a straight line passing through point (5,2) and the intercept on the x-axis is twice that on the y-axis is ()
A. 2X + Y-12 = 0b. X + 2y-9 = 0 or 2x-5y = 0C. X-2y-1 = 0d. 2x + y-l2 = 0 or 22-5y = 0

When the line passes through the origin, the slope of the line is 25, so the equation of the line is y = 25X, that is, 2x-5y = 0. When the line does not pass through the origin, let the intercept of the line on the x-axis be K, then the intercept on the y-axis be 2K, so the equation of the line is XK + Y2K = 1. Substituting the point (5, 2) into the line, we can get 5K + 22K = 1, and the solution is k = 6. So the equation of the line is X6 + Y12 = 1, that is 2x + y- 12 = 0

If the inclination angle of the straight line L is 3 π / 4 and the intercept on the Y axis is - 5, the general equation of the straight line is?

The tilt angle is 3 π / 4
The slope is k = Tan (3 π / 4) = - 1
The linear equation is y = - X-5
That is, x + y + 5 = 0

A linear equation passing through point a (- 5,2) with an intercept on the x-axis equal to twice the intercept on the y-axis

Because the intercept of X is twice that of Y, set the straight line y = KX + B, then k = ± 0.5, then the point (- 5,2) is brought in
B = - 0.5 or 4.5
So the linear equation is: y = - 0.5x-0.5 or y = 0.5x + 4.5

If the line L passes through point a (- 2, - 3) and the intercept on two coordinate axes is equal, the equation of line L is obtained
Who's right

If the line L passes through the point a (- 2, - 3) and the intercept on the two coordinate axes is equal, let the x-axis cut-off point (m, 0) and the y-axis cut-off point (0, m), then the line:
K=(y2-y1)/(x2-x1)=(m-0)/(0-m)=-1；
Let the linear equation be y = KX + B, and substitute k = - 1 and point a (- 2, - 3) into the equation
(- 3) = (- 1) * (- 2) + B, so B = - 5;
Finally, the linear l equation is as follows:
y=-x-5

Let the equation of line L (a + 1) x + y + x-a = 0, (a belongs to R) if the intercept of L on two coordinate axes is equal, the equation of line L is obtained
It's a process

It is known that (a + 1) x + y + x-a = 0,
So, (a + 2) x + Y-A = 0
When x = 0, y = a
When y = 0, x = A / (a + 2)
Because the intercept of L on the two axes is equal
So, a = A / (a + 2)
a[1-1/(a+2)]=0
That is, a = 0 or 1-1 / (a + 2) = 0
The solution is a = 0 or a = 1
So the equation of the line L is y = - 2x, or y = - 3x + 1

A linear equation () This is a multiple choice question A：2x+y-12=0 B: 2X + Y-12 = 0 or 2x-5y = 0 C: X + 2y-9 = 0 or 2x-5y = 0 D: X + 2y-9 = 0 or 2x + 5Y = 0 Requirement: not only options