What is the equation of a straight line passing through the intersection of two straight lines: L1: 2x-2y + 1 = 0, L2: LX + 3y-2 = 0, and with equal intercept on two coordinate axes

What is the equation of a straight line passing through the intersection of two straight lines: L1: 2x-2y + 1 = 0, L2: LX + 3y-2 = 0, and with equal intercept on two coordinate axes

The intersection of L1: 2x-2y + 1 = 0, L2: LX + 3y-2 = 0 is (1 / 8,5 / 8)
therefore
one
Let the line be y = KX
5/8=k*1/8
k=5
y=5x
two
Let the line be
x/a+y/a=1
1/8a+5/8a=1
6=8a
a=3/4
therefore
The straight line is:
x+y=3/4
y=-x+3/4

The equation of the line with intercept of 4 and - 3 on X and Y axes is______ ．

The equation of the line with intercept of 4 and - 3 on x-axis and y-axis is X4 + y − 3 = 1, which is changed to 3x-4y-12 = 0. So the answer is: 3x-4y-12 = 0

Find the equation of a line which is tangent to the circle x ^ 2 + y ^ 2-4x + 2 = 0 and has the same intercept on the X and Y axes

The intercept is equal on the X and Y axes
Let the linear equation be
y=±x+b
That is ± X-Y + B = 0
Circle x ^ 2 + y ^ 2-4x + 2 = 0
(x-2)^2+y^2=2
Distance from center of circle (2,0) to straight line = √ 2
|±2+b|/√2=√2
|±2+b|=2
B = 4, - 4, 0 (rounding off)
Linear equation
y=x+4
y=-x-4

Through the intersection of two straight lines l1:2x-y + 1 = 0, L2: x + 3y-2 = 0, and the line equation with equal intercept on two coordinate axes can be ()
A. 7x+7y+4=0B. 7x+7y-4=0C. 7x-7y+6=0D. 7x-7y-6=0

Simultaneous 2x − y + 1 = 0x + 3Y − 2 = 0, the solution is x = − 17Y = 57. The intersection of two lines L1 and L2 is p (− 17, 57). When the line passes through the origin, the linear equation is y = − 1757x = - 15x. When the line does not pass through the origin, let the linear equation be x + y = a, and P (− 17, 57) be substituted to get − 17

The intercept of a line on the y-axis is - 2, and it is perpendicular to the line 2x + 3Y + 1 = 0

The intercept of a line L on the y-axis is - 2
L over point (0, - 2)
∵ perpendicular to the straight line 2x + 3Y + 1 = 0
∴k=3/2
The equation of line L: y + 2 = 3 / 2x
That is, 3x-2y-4 = 0

A linear equation perpendicular to 2x + 3y-2 = 0 with intercept 2 on the y-axis

Line 2x + 3y-2 = 0
3Y=-2X+2
Y = - 2x / 3 + 2 / 3, K value is - 2 / 3
So the K value of the line perpendicular to it is - 1 ÷ (- 2 / 3) = 3 / 2
And the intercept of y-axis is 2
So the linear equation is y = 3x / 2 + 2
That is, 3x-2y + 4 = 0

If the intercept of the line L on the Y axis is 2 and it is perpendicular to the line L ′: x + 3y-2 = 0, then the equation of L is______ ．

The slope of the straight line L ′: x + 3y-2 = 0 is equal to - 13, so the slope of the straight line L is equal to 3. According to the intercept of the straight line L on the Y axis is 2, so the equation of L is & nbsp; y = 3x + 2, that is, 3x-y + 2 = 0, so the answer is 3x-y + 2 = 0

Find the slope, vertical distance and cross section of the following lines (1) 3x + Y-5 = 0 (2) 7x + 6y-3 = 0

（1）3x+y-5=0
Slope = - 3
Let x = 0 lead to a vertical Street distance of 5
Let y = 0 give a cross section of 5 / 3
2)7x+6y-3=0
Slope = - 7 / 6
Let x = 0 lead to 1 / 2 vertical Street distance
Let y = 0 give a cross section of 3 / 7

What should the figure 7x-6y + 4 = 0 look like, the slope of X + 2Y = 0 and the intercept on the Y axis
Please tell me the graph of X + 2Y = 0

X + 2Y is a straight line intersecting Y-axis and (0 2 / 3), x-axis and (- 4 / 7 0)! The slope of X + 2Y is - 1 / 2, and the intercept is 0

The slope is 5, the intercept on the Y axis is negative 2, the intercept on the X and Y axes are negative three and negative one, respectively

The intercepts on the X and Y axes are negative three and negative one, respectively
What does that mean?
The first half is y = 5x-2
I don't understand the meaning of the latter part
I see
It's a new problem
y=-1/3x-1