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The intercept of y = 4-2x on Y axis is
The intercept is the ordinate of the intersection of the line and the y-axis
When x = 0, y = 4
So the intercept of y = 4-2x on the Y axis is 4
Intercept of line 2x + Y-7 = 0 on y-axis
The answer is 7!
Given that the inclination angle of line L α = 2x / 3 and the intercept on Y axis is 3, the equation of line L is obtained?
The inclination angle of solution line L α = 2 π / 3
That is, the slope of the straight line k = tan2 π / 3 = tan120 ° = - √ 3
The intercept on the y-axis is 3
Then the equation of the line y = - √ 3x + 3
The equation of a line which is perpendicular to the line 2x + Y-1 = 0 and whose intercept on the y-axis is - 2 is
This is easy to do
2X + Y-1 = 0, y = - 2x + 1, the slope is - 2
Because the two lines are perpendicular, the slope of line L is 1 / 2
So y = 1 / 2x + B
And because the intercept on the y-axis is - 2
So when x = 0, B = - 2
So we get y = 1 / 2x-2
The general formula is 2Y = x-4, x-2y-4 = 0
The answer must be right
I hope it can help you
You can keep asking me if you don't know
If the point P (m, m-1) is on the X axis, then the point P is symmetric about the Y axis. What is the P coordinate?
The point P (m, m-1) is on the x-axis, M-1 = 0
m=1
P(1.0)
Then the point P is symmetric about the Y axis. What is the P coordinate?
P(-1,0)
Given that the coordinates of points a and B are (2m + N, 2). (1, n-m), when m and N are the values, AB is symmetric about X axis
When m and N are equal, a and B are symmetric about y axis?
If AB is symmetric about the X axis
So 2m + n = 1
n-m=-2
Two equations are established, and the solution is obtained
n=-1,m=1
If it is symmetric about the Y axis
So 2m + n = - 1
n-m=2
The solution is n = 1, M = - 1
Given that points m (a, b) and N are symmetric about X axis, points P and N are symmetric about y axis, and points Q and P are symmetric about x + y = 0, then the coordinates of point q are ()
A. （a，b）B. （b，a）C. （-a，-b）D. （-b，-a）
Given that the points m (a, b) and N are symmetric about the x-axis, ｜ n (a, - b), the points P and N are symmetric about the y-axis, ｜ P (- A, - b), and the points Q and P are symmetric about the line x + y = 0, then q (B, a)
The point coordinates of M (1,2) about X axis symmetry are ()
（1,-2）
PS. on the coordinate axis, the abscissa of the original coordinate does not change and the ordinate is the opposite number when the coordinate is symmetrical about the X axis; when the coordinate is symmetrical about the Y axis, the ordinate of the original coordinate does not change and the abscissa is the opposite number; when the coordinate is symmetrical about the origin, the abscissa and ordinate of the original coordinate become the opposite number
Example: the point coordinates of M (1,2) are (1, - 2) about X axis symmetry
The coordinates of point m (1,2) symmetric about y axis are (- 1,2)
Point m (1,2) is symmetric with respect to the origin and its coordinates are (- 1, - 2)
Given that m and N are symmetric about y axis, and that M is on hyperbola y = 1 / (2x), n is on straight line y = - x + 3, let m coordinate be (a, b)
Then the vertex coordinates of y = - ABX & # 178; + (a + b) x are
Can a + B be negative root 11
Because the coordinates of point m are (a, b),
So the coordinates of point n are (- A, b)
By substituting hyperbola and straight line respectively, we get
b=1/(2a),b=-a+3,
That is ab = 1 / 2, a + B = 3
So y = - ABX & # 178; + (a + b) X
=-(1/2)x²+3x
=-(1/2)(x-3)² +9/2
The vertex coordinates are (3,9 / 2)
It is known that two points are symmetric about y axis, and point m is on hyperbola y = 1 / 2x, and point n is on straight line y = x + 3
Given that m and N are symmetric with respect to y axis, and point m is on hyperbola y = 1 / 2x, and point n is on straight line y = x + 3, let the coordinate of point m be, then the quadratic function y = - ABX ^ 2 + X has maximum or minimum value, and what is the maximum "small" value. The problem is how to substitute m (a, b), n (- A, b) into y = 1 / 2x and y = x + 3 to get b = 1 / 2a, B = 3-A, and then how to get a = 2, B = 1
Trouble B = 1 / 2a, can we get 2B = a? Or can 1 / 2A = 3-A get 3 / 2A = 3?
B=1/2A,B=3-A
1/2A=3-A
3/2A=3
A=2
Substituting B = 1 / 2A
B=1
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