The intercept of the line X-Y + 1 = 0 on the x-axis and y-axis are?

The intercept of the line X-Y + 1 = 0 on the x-axis and y-axis are?

Reduced intercept equation
x/1+y/（-1）=1
So the intercept of the x-axis is 1
Y-intercept-1
Or let x = 0, y = - 1, which is the intercept
Let y = 0, x = 1, which is the intercept of X axis

The intercept on the y-axis is 0. What is the intercept on the x-axis

I said that it coincides with the x-axis, that is, it does not cut off the x-axis, so there is no ending, so the answer is: there is no intercept

The equation of a line passing through point P (- 2,1) with equal intercept on x-axis and y-axis is

If passing through point P (- 2,1) and the intercept on x-axis and y-axis is equal, then "a = B"“
k=1
y-1=1(x+2)
x-y+3=0

The equation of line L passing through point P (- 3, - 4) with equal intercept on x-axis and y-axis is______ ．

When the line passes through the origin, the slope is - 4-0-3-0 = 43, and the linear equation is y = 43 & nbsp; X, that is, 4x-3y = 0. When the line does not pass through the origin, let the linear equation XA + Ya = 1, and substitute the point P (- 3, - 4) to get - 3A + - 4A = 1, ｜ a = - 7, ｜ the equation of the line is X-7 + Y-7 = 1, x + y + 7 = 0. To sum up, the equation of the line is 4x-3y = 0, or x + y + 7 = 0, so the answer is: 4x-3y = 0, or x + y + 7 = 0