The intercept of line 7x + 2y-5 on the y-axis is?

The intercept of line 7x + 2y-5 on the y-axis is?


Y = KX + B, B is the intercept of the line on the Y axis
For the straight line 7x + 2y-5 = 0, it can be transformed into a point oblique y = - 7x / 2 + 5 / 2, B = 5 / 2
The intercept of the line 7x + 2y-5 = 0 on the Y axis is 5 / 2



If the distance from the origin to the line L: x + 2Y + k = 0 is 1, then the intercept of the line L on the Y axis is 1


The distance of X + 2Y + k = 0 is 1
Bring in the formula of the distance from the origin to the straight line
|k|/√5=1
Get k = √ 5 or K = - √ 5
therefore
The intercept of the line on the Y axis is √ 5 or - √ 5



Given that the equation of line L is 3x-2y = 6, what is the intercept of line L on Y axis


3x-2y=6
x/2+y/(-3)=1
The intercept is - 3



If the intercept of a line ax-6y-12a = 0 (a ≠ 0) on the x-axis is three times of its intercept on the y-axis, then a is equal to 0______ .


It can be seen from the meaning of the question: the linear equation can be reduced to X12 + y − 2A = 1, and the intercept of the line on the x-axis is three times of its intercept on the y-axis, so 12 = 3 (- 2A), the solution is a = - 2, so the answer is: - 2