The intercept of the line x + 6y + 2 = 0 on the x-axis and y-axis are______ ．

The intercept of the line x + 6y + 2 = 0 on the x-axis and y-axis are______ ．

Method 1: transform the equation x + 6y + 2 = 0 of the straight line into the equation of intercept: X − 2 + Y13 = 1, the intercept on the x-axis and y-axis are - 2, - 13 respectively. Method 2: ∵ the straight line x + 6y + 2 = 0, when x = 0, y = - 13, when y = 0, x = - 2, that is, the intercept on the x-axis and y-axis are - 2, - 13 respectively. So the answer is: - 2, - 13

Given that f (x) = ax ^ 2 + BX + C (a ≠ 0), when x = 3, take the minimum value of 4, and the intercept of the image on the Y axis is 13, find the value of a, B, C

The image is a quadratic function. The solution of parabola f (0) = 13-b / 2A = 3f (3) = 4 is a = 1, B = - 6, C = 13. The description is as follows: the intercept on the y-axis is 13, that is, f (0) = 13, that is, C = 13, and the minimum value 4 when x = 3. It shows that the opening is upward, a > 0 and the axis of symmetry is x = 3, that is - B / 2A = 3, B = - 6A. From F (3) = 4, 9A + 3B + C = 4, a = 1, B