In solving the equations {ax + by = C ① ax by = - 3 ②, Xiao Ming mistook - 3 in equation ② as 3 and got the solution {x = 3, y = 6 because of carelessness The solution is {x = 5, y = 18

In solving the equations {ax + by = C ① ax by = - 3 ②, Xiao Ming mistook - 3 in equation ② as 3 and got the solution {x = 3, y = 6 because of carelessness The solution is {x = 5, y = 18

In solving the equations {ax + by = C, ① ax by = - 3, ②, Xiao Ming mistook - 3 in equation ② for 3 and got the solution {x = 3, y = 6. Xiao Gang mistook the value of B in equation ① and got the solution {x = 5, y = 18. Finding the value of a, B, C and substituting Xiao Ming's data into 3A + 6B = C. (1) 3a-6b = 3. (2) (1) + (2) got 6A = C +

The sum of the intercept of the line ax + by ab = 0 (AB ≠ 0) on the two axes is
A. A + B B. │ a │ + B │ C. │ a + B │ D. can only be positive

D

Given that the line ax + by + C = 0 (AB is not equal to 0), when a, B, C meet what conditions, 1. The line passes through the origin? 2. The sum of intercept on two coordinate axes is 0?

The coordinate is (x, y), the origin coordinate is (0,0), passing through the origin is x = 0, y = 0, substituting ax + by + C = 0, we can see that C = 0
The intercept point on the x-axis is y = 0. At this time, we can see that x = - C / A. similarly, when the intercept point on the y-axis is y = - C / B, the sum is 0
C / A + C / b = 0, at this time, in addition to C = 0 (that is, crossing the origin, two intercept are 0, and 0), another result is
A + B = 0, or a and B are opposite to each other

Two straight lines L1: MX + 8y + n = 0 and L2: 2x + MY-1 = 0 are known. Try to determine the value of M, n so that (1) L1 ‖ L2; (2) L1 ⊥ L2, and the intercept of L1 on the Y axis is - 1

(1) When m = 0, it is obvious that L1 and L2 are not parallel. & nbsp; when m ≠ 0, from M2 = 8m ≠ n-1 & nbsp; we get m · M-8 × 2 = 0, M = ± 4,8 × (- 1) - n · m ≠ 0, n ≠± 2, so when m = 4, n ≠ - 2, or M = - 4, n ≠ 2, L1 ‖ L2. (2) if and only if M · 2 + 8 · M = 0, that is, when m = 0, L1 ‖ L2