The function y = 2k-3 of 2x, when x is less than 0, y decreases with the increase of X, then the value range of K is

The function y = 2k-3 of 2x, when x is less than 0, y decreases with the increase of X, then the value range of K is

Because x is less than 0, so 2x is less than 0, the denominator is negative, and because y decreases with the increase of X, the result of 2k-3 of 2x is negative. Now the denominator is negative, if you want to calculate a negative result, the numerator must be greater than 0 to ensure that the result is negative, so 2k-3 is greater than 0, solve the inequality 2k-3 is greater than 0, get k greater than 3 / 2!

Function y = 2k-5 / x, X

According to the meaning of the title
2k-5>0
2k>5
k>2.5
The range of K is k > 2.5

If the image of the linear function y = (K + 2) x-2k + 3 does not pass through the fourth quadrant, then the value range of K is______ ．

If the image of a linear function y = (K + 2) x-2k + 3 does not pass through the fourth quadrant, then K + 2 > 0 and - 2K + 3 ≥ 0, the solution is - 2 < K ≤ 32, so the answer is: - 2 < K ≤ 32