The linear equation with a slope of - 2 and an intercept of 3 on the y-axis is () A. 2x+y+3=0B. 2x-y+3=0C. 2x-y-3=0D. 2x+y-3=0 | Math enthusiast | Mathematical art

The linear equation with a slope of - 2 and an intercept of 3 on the y-axis is () A. 2x+y+3=0B. 2x-y+3=0C. 2x-y-3=0D. 2x+y-3=0

The linear equation with the slope of - 2 and the intercept of 3 on the Y axis is y = - 2x + 3, which is reduced to 2x + Y-3 = 0

It is known that the slope of the straight line L is 3 and passes (0,4). Find the equation of the straight line where the intercept of the x-axis is 3 and perpendicular to L

The vertical slope is - 1 / 3
y=-x/3+b
The intercept of the x-axis is 3
x=3,y=0
So 0 = - 1 + B
b=1
So y = - X / 3 + 1
That is, x + 3y-3 = 0

A linear equation with a slope of minus half and an intercept of 5 on the y-axis

y=-x/2+5.

The intercept ratio of the straight line L on the X and Y axis is 2:3, and it passes through the point P (4,9)

Solution
The intercept ratio of L on X and Y axis is 2:3
Let l be a linear equation
x/2k+y/3k=1
Substituting (4,9) into
2/k+3/k=1
∴k=5
∴x/10+y/15=1
That is 3x + 2Y = 30

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