If y = (1-2k) x-k decreases with the decrease of X, and the image of this function does not pass through the second quadrant, what is the value range of K

If y = (1-2k) x-k decreases with the decrease of X, and the image of this function does not pass through the second quadrant, what is the value range of K

If y = (1-2k) x-k, y decreases with the decrease of X
Then: 1-2k > 0
k

Given a linear function y = (2k-1) x + 3-2k, when y decreases with the increase of X, the image does not pass through which quadrant? No matter what the value of K is, the linear function must pass through a certain point?

Because the linear function y = (2k-1) x + 3-2k, when y decreases with the increase of X
So 2k-1

Given that the image of a linear function y = (k-1) x + B passes through the first, second and third quadrants, what is the value range of K

It's going through quadrant one, two, three, so it's going up
So k-1 > 0
k>1

If the distance between the image of function y = KX + 2 and the intersection of X axis and Y axis is √ 5, then the value of K is_____ (process)

If the distance between the image of function y = KX + 2 and the intersection of X axis and Y axis is √ 5, then the value of K is_____ .
x=0 y=2
y=0 x=-2/k
√(4+4/k²)=√5
therefore
k²=1
We get k = - 1 or K = 1