Let the line L intersect the x-axis and y-axis with the point AB respectively. If the line M: y = KX + T (t greater than 0) is parallel to the line L and intersects the x-axis with the point C, the area s of the triangle ABC is obtained with respect to t In ABC, the relation between S and t is {s = 9-2 / 3T (0 < T < 3)} S = 2 / 3t-9 (T > 6) this answer says that point C is on the positive half of the x-axis, but it can also say that when C is on the left side of B, s = 9-2 / 3T, so point C is on the negative half of the x-axis. What's the matter?

Let the line L intersect the x-axis and y-axis with the point AB respectively. If the line M: y = KX + T (t greater than 0) is parallel to the line L and intersects the x-axis with the point C, the area s of the triangle ABC is obtained with respect to t In ABC, the relation between S and t is {s = 9-2 / 3T (0 < T < 3)} S = 2 / 3t-9 (T > 6) this answer says that point C is on the positive half of the x-axis, but it can also say that when C is on the left side of B, s = 9-2 / 3T, so point C is on the negative half of the x-axis. What's the matter?


∵ the intersection of line L and X, Y axes and points a, B ∵ a, B coordinates are (O, 6) / (3,0) ∵ L ∥ m ∥ m is y = - 2 + T ∥ C point coordinates are (2 / T, 0) ∵ t ∥ 0 ∥ 2 / T ∥ 0 ∥ point C is on the positive half axis of X axis ∥ when C is on the left side of B, s = 9-2 / 3T, and on the right side of B, x = 2 / 3t-9



If the area of △ abo (o is the coordinate origin) is 2, then the value of B is______ .


If the line y = KX + B passes through the point a (- 2, 0), and the intersection coordinate of the line y = KX + B and the Y axis is (0, b), then the area of △ ABO is 12 × 2 · B = 2, and the solution is b = 2. So the value of B is 2