It is known that the linear equation is ax + by + C = 0. When a, B and C are 0 respectively, the position and slope of the line are the same

It is known that the linear equation is ax + by + C = 0. When a, B and C are 0 respectively, the position and slope of the line are the same

A=0
Time slope = 0
B = 0, the slope does not exist
C=0
Slope = - A / b

1. A solution of the equation (AX + by-7) 2 + | ax by + 3 | = 0 of X and Y is {x = 1, y = - 1}. Find the value of 2A + B
2. Given the square of (2x-y-5) + | one third x + Y-2 | = 0, find the value of 3x + y

(1) Because (AX + by-7) ^ 2 + | ax-by + 3 | = 0 and (AX + by-7) ^ 2 ≥ 0, | ax-by + 3 | ≥ 0, so ax + by-7 = 0, ax-by + 3 = 0, substituting x = 1, y = - 1 into the above two equations, we get a-b-7 = 0A + B + 3 = 0, and the solution is a = 2B = - 5, so 2A + B = 4-5 = - 1 (2) because (2x-y-5) ^ 2 + | X / 3 + Y-2 | = 0, and (2x -