It is known that the intercept of lines L1 and L2 on x-axis is equal, and their inclination angles are complementary, and the line L1 passes through point P (- 3,3). If the distance between point Q (2,2) and L2 is 1, the equation of L2 is solved

It is known that the intercept of lines L1 and L2 on x-axis is equal, and their inclination angles are complementary, and the line L1 passes through point P (- 3,3). If the distance between point Q (2,2) and L2 is 1, the equation of L2 is solved


Let the equation of line L2 be y = K (x-a), then the equation of line L1 is y = - K (x-a). ∵ the distance from point Q (2,2) to L2 is 1, | K (2 − a) − 2 | 1 + K2 = 1. (1) because line L1 passes through point P (- 3,3), then 3 = - K (- 3-A). (2) from (2), Ka = 3-3k, substituting (1), then | 5K − 5 | 1 + K2 = 1, | 12k2-25k + 12 = 0 )So the equation of line L2 is: 4x-3y + 3 = 0, or 3x-4y-3 = 0



If the intercept of line L1 and L2 is m on X axis and N on Y axis, the relationship between L1 and L2 is
Will it be parallel
Is there only overlap


Because according to the question, L1 and L2 pass through two points (m, 0) and (n, 0). According to the theorem that two points determine a straight line, the straight line coincides