The intersection of y = 2x + m and y = 3x + 3 is in the second quadrant

The intersection of y = 2x + m and y = 3x + 3 is in the second quadrant


By solving the equations y = 2x + my = 3x + 3, we get x = m − 3Y = 3M − 6. ∵ the intersection point is in the second quadrant, ∵ m − 3 < 03m − 6 > 0, we get 2 < m < 3. Therefore, the value range of M is 2 < m < 3



The intersection of the line y = 2x + m and the line y = 3x + 3 is in the second quadrant. Find the value of M. the intersection in is (M-3,


The results show that the intersection point is (m-3,3m-6)
The coordinate point of X is m-3
The coordinate point of Y is 3m-6
Because the intersection is in the second quadrant, so x0
So m-32)
SO 2