What's the range of the slope of the line

What's the range of the slope of the line

The range of inclination angle is [0, π]
The slope range is r

Given that the line L passes through the point m (2,3), and the intercept on the x-axis and y-axis is equal, the equation of the line L is obtained

When the intercept is 0, y = 1.5x
When the intercept is not zero, we can know that the slope of this line is - 1,
So, the linear equation is y = - x + 5

Given that the line L passes through the point m (3, - 2), and the intercept on the two coordinate axes is equal, then the equation of L is? To be solved in detail

① When l crosses the origin
L：y+2=-2/3(x-3)
∴2x+3y=0
② When l is not the origin
Let L: X / A + Y / b = 1
∵a=b
3/a-2/b=1
∴a=b=1
∴L:x+y-1=0
In conclusion, l: 2x + 3Y = 0 or x + Y-1 = 0

Given that a line L passes through a point P (3,4), its intercept on the y-axis is twice that on the x-axis, the equation of the line L is obtained;

Let the intercept on the x-axis be a and the intercept on the y-axis be 2A
Then the linear equation is x / A + Y / (2a) = 1
Substituting point P, 3 / A + 4 / (2a) = 1
a=5
So the straight line is: X / 5 + Y / 10 = 1