Given that x|k| [absolute value] + 21 = 0 is a linear equation with one variable, then K=

Given that x|k| [absolute value] + 21 = 0 is a linear equation with one variable, then K=

solution
The equation is a linear equation of one variable
∴/k/=1
∴k=1
Or K = - 1

It is known that including (the absolute value of k-1) + (k-1) x + 3 = 0 is the value of K for the linear equation of one variable with respect to X

K is - 1, if it is 1, it is not a linear equation with one variable

It is known that the absolute value of K of equation (K-3) y - 2, + 5 = K-4 is a linear equation of one variable with respect to y, and the value of K can be obtained

Because the absolute value of K of equation (K-3) y - 2, + 5 = K-4 is a linear equation of one variable with respect to y, the coefficient of Y term is 1
So the absolute value of K - 2 = 1
The absolute value of k = 3
K = 3 or - 3
If k = 3, then the coefficient of Y is 3-3 = 0
So k = - 3
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It is known that (the absolute value of K-2) times the square of X - (K-2) times x + 6 = 0 is a linear equation of one variable with respect to x, then k =?

It is known that (absolute value of K-2) multiplied by the square of X - (K-2) multiplied by X + 6 = 0 is a univariate linear equation about X, | K | - 2 = 0; k = ± 2; K-2 ≠ 0; K ≠ 2; k = - 2; Hello, I'm glad to answer for you. Skyhunter 002 will answer for you

If (x ^ m ／ x ^ 2 × n) ^ 3 ／ x ^ (m-n) is the same as - 1 / 4x ^ 2, and 2m + 5N = 7, find the value of 4m & # 178; - 2n & # 178

(x ^ m ﹣ x ^ 2 × n) ^ 3 ﹣ x ^ (m-n) = (x ^ (m-2n)) ^ 3 ﹣ x ^ (m-n) = x ^ 3 (m-2n) ﹣ x ^ (m-n) = x ^ (3m-6n-m + n) = x ^ (2m-5n) is the same as - 1 / 4x ^ 2, so 2m-5n = 2. Because 2m + 5N = 7, 4m = 9m = 9 / 4N = 1 / 24m & ﹣ 178; - 2n & ﹣ 178; = 4 * (81 / 16) - 2 * (1 / 4) = 81 / 4 - 1 / 2 = 79

If (XM ﹣ X2N) 3 ﹣ xm-n is the same as 4x2, and 2m + 5N = 7, find the value of 4m2-25n2

(XM ﹣ X2N) 3 ﹣ xm-n = (xm-2n) 3 ﹣ xm-n = x3m-6n ﹣ xm-n = x2m-5n, because it is the same as 4x2, so 2m-5n = 2, and 2m + 5N = 7, so 4m2-25n2 = (2m) 2 - (5N) 2, = (2m + 5N) (2m-5n), = 7 × 2, = 14

If (x ^ m / x ^ 2n) ^ 3 / x ^ M-N is the same as 4x ^ 2, and 2m + 5N = 6, find the value of 4m ^ 2-25n ^ 2

A
(x^m/x^2n)^3/x^(m-n)
=[x^(m-2n)]^3/x^(m-n)
=x^3(m-2n)/x^(m-n)
=x^(3m-6n-m+n)
=x^(2m-5n)
It is the same as 4x ^ 2
therefore
2m-5n=2
2m+5n=6
Solving equations
have to
m=2
n=2/5
4m^2-25n^2
=4×4-25×4/25
=16-4
=12

If (x ^ m / x ^ 2n) ^ 3 / x ^ M-N is the same as 4x ^ 2, and 2m + 5N = 6, find the value of 4m ^ 2-2n ^ 2

(x^m/x^2n)^3/x^(m-n)
=[x^(m-2n)]³/x^(m-n)
=x^(3m-6n)/x^(m-n)
=x^[(3m-6n)-(m-n)]
=x^(2m-5n)
(x ^ m / x ^ 2n) ^ 3 / x ^ M-N is the same as 4x ^ 2
The exponents of X are equal, that is 2m-5n = 2
Another 2m + 5N = 6 ②
① (2) M = 2, n = 2 / 5
∴4m^2-2n^2
=4×4-2×4/25
=16-8/25
=392/25

(x ^ m ／ x ^ 2n) ^ 3 ／ x ^ M-N is the same as 1 / 2x ^ 2, and 2m + 5N = 7 is the value of 4m ^ 2-25n ^ 2

（x^m÷x^2n)^3÷x^(m-n)
=x^(3m-6n)÷x^(m-n)
=x^(2m-5n)
∵ is similar to 1 / 2x ^ 2
∴2m-5n=2
∵2m＋5n＝7
∴4m^2－25n^2
=(2m+5n)(2m-5n)
=7×2
=14

If (x ^ m ／ x ^ 2n) ^ 3 ／ x ^ (m-n) and x ^ 2 are of the same kind, and 2m + 5N = 6, find 4m ^ 2-25n ^ 2

（x^m÷x^2n)^3÷x^（m-n）=(x^(m-2n))^3÷x^（m-n）=x^(3m-6n-m+n)=x^(2m-5n)
∵ (x ^ m △ x ^ 2n) ^ 3 △ x ^ (m-n) and x ^ 2 are of the same kind
The same kind of terms as x ^ 2
∴2m-5n=2
So 4m ^ 2-25n ^ 2 = (2m + 5N) (2m-5n) = 12