As shown in the figure, it is known that the area of the square oabc is 9, point O is the origin of the coordinate, point a is on the x-axis, point C is on the y-axis, point B is on the image of the function y = KX (k > 0, x > 0), point P (m, n) is any point on the image of the function y = KX (k > 0, x > 0). Through point P, make the perpendicular lines of the x-axis and y-axis respectively, and the perpendicular feet are e and F, and let the plane of the non coincidence part between the rectangular oepf and the square oabc The product is S. (1) find the value of the coordinates of point B and K. (2) find the coordinates of P when s = 92. (3) write the functional relation of s with respect to M

As shown in the figure, it is known that the area of the square oabc is 9, point O is the origin of the coordinate, point a is on the x-axis, point C is on the y-axis, point B is on the image of the function y = KX (k > 0, x > 0), point P (m, n) is any point on the image of the function y = KX (k > 0, x > 0). Through point P, make the perpendicular lines of the x-axis and y-axis respectively, and the perpendicular feet are e and F, and let the plane of the non coincidence part between the rectangular oepf and the square oabc The product is S. (1) find the value of the coordinates of point B and K. (2) find the coordinates of P when s = 92. (3) write the functional relation of s with respect to M

(1) The area of oabc of ∵ square is 9, ∵ OA = OC = 3, ∵ B (3,3). And ∵ point B (3,3) on the image of function y = KX (k > 0, x > 0), ∵ k = 9 (2) It can be divided into two cases: ① when point P1 is on the left side of point B, ∵ P1 (m, n) is on the function y = KX, ∵ Mn = 9. ∵ then s = m (n-3) = 92 ∵ M = 32, ∵ n = 6. ∵ P1 (32, 6); ② when point P2 is on the right side of point B or B, ∵ P2 (m, n) is on the function y = KX, ∵ Mn = 9. ∵ s = n (M-3) = mn-3, n = 92