Given the set = {- 1, a & # 178; - 3, a & # 178; - 3, a & # 178; + 1}, and the intersection of a and B = {- 2}, find the value of real number a and the union of a and B

Given the set = {- 1, a & # 178; - 3, a & # 178; - 3, a & # 178; + 1}, and the intersection of a and B = {- 2}, find the value of real number a and the union of a and B

Does your question seem to lack conditions?

Given that the minimum value of function y = (AX ^ 2 + BX + C) / (x ^ 2 + 2) is 2 and the maximum value is 6, find the value of real numbers a and B

Y = (AX ^ 2 + BX + C) / (x ^ 2 + 2) = [a (x ^ 2 + 2) + (b-2a) x + C] / (x ^ 2 + 2) = a + (b-2a) x / (x ^ 2 + 2) + C / (x ^ 2 + 2), because (x ^ 2 + 2) > = 2, so 0

Mathematics of senior one: if we know the quadratic function f (x) = ax ^ 2 + X, and 0

When a = 0, it is true (note that the function topic should first consider the case that the parameter is zero)
When a is not equal to, |f (- 1 / 2a)|

The function f (x) = 4x2 MX + 5 is an increasing function in the interval [- 2, + ∞) and a decreasing function in the interval (- ∞, - 2). The value of real number m is equal to ()
A. 8B. -8C. 16D. -16

∵ the function f (x) is an increasing function in the interval [- 2, + ∞), a decreasing function in the interval (- ∞, - 2), x = - 2 is the symmetry axis of the quadratic function, x = − M2 × 4 = M8 = − 2, and the solution is m = - 16

Given the function f (x) = x ^ 2 + ax INX, if the function FX is a decreasing function on [1,2], the value range of a is obtained

-LNX is a decreasing function, regardless of the quadratic function in front of it. If the axis of symmetry - A / 2 is greater than or equal to 2, you should solve the inequality yourself

Given function FX = (1-x) / ax + INX:
1: FX is an increasing function on (1, + ∞). Find the value range of positive real number a 2: when a = 1, the maximum and minimum values on {1 / 2,2}

1 f (x) = (1-x) / ax + LNX = 1 / (AX) - 1 / A + LNX, a is a positive real number, the domain x > 0f '(x) = 1 / X-1 / (AX ^ 2), when x = 1 / A, f' (x) = 0, when 00, so when x ∈ [1 / A, inf], the function is an increasing function, so when 1 / a ≤ 1, that is, a ≥ 1, f (x) is an increasing function on (1, + ∞), so when a ≥ 12a = 1, f (x) = 1 / x +

The number of zeros of function FX = x Λ 2 - / 2x / - 1-A is discussed

Let t = | x | > = 0
Then f (x) = T ^ 2-2t-1-a = (t-1) ^ 2-2-a
When - 2-A = 0, i.e. a = - 2, the zero point is t = 1, i.e. x = - 1 and 1, and there are two zeros;
When - 2-A > 0, that is a

The number of zeros of function f (x) = LNX + 2x-6______ ．

∵ the number of zeros of the function f (x) = LNX + 2x-6 is transformed into the number of roots of the equation LNX = 6-2x, and the functions expressed by left and right expressions are drawn respectively: from the image, we can get that there is only one intersection point between the two functions

If the function f (x) = AX2 + 2x + 1 has at least one zero point in the interval (- ∞, 0), then the value range of real number a is______ ．

When a = 0, f (x) = 2x + 1, zero point is x = - 12, on the left side of the origin, if a < 0, then △ = 4-4a > 0 is tenable, so f (x) has zero point, and x1 · x2 < 0, at least one zero point is negative, if a > 0, then a ≤ 1, two zeros satisfy X1 + x2 = - 2A < 0, x1 · x2 = 1A > 0

Given the set a = {x | X & # 178; + 4x = 0}, the set B = {x | X & # 178; + 2 (a + 1) + A & # 178; - 1 = 0, a ∈ r}, if the intersection B of a is equal to B, find the value of real number a
If a and B are equal to B, find the value of real number a

1.
A={X|x^2+4x=0}={-4,0} ,
The intersection of a and B = B indicates that B is a subset of A
B is a quadratic equation
If there is no solution, it is an empty set
Discriminant = 4 [(a + 1) &# 178; - (A & # 178; - 1)]