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If the equation AX-1 = x + a about X has no solution, then the value of constant a should be () A. 1B. -1C. ±1D. 0
The original equation is transformed into (A-1) x = a + 1. It is known that the equation has no solution, so a − 1 = 0A + 1 ≠ 0, and the solution is a = 1. Therefore, the value of a should be 1
Given that a is an integer and 0 & lt; a & lt; 10, please find a specific value of a, which is that the solution of equation 1-ax / 2 = - 5 is even
1-ax/2=-5
ax/2-5=1
Double two on both sides
ax-10=2
ax=12
Because the solution of the equation is even
That is, X is even
Because a is an integer and 0
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