Given the equation about x [(AX) / X-1] - [2 / (1-x)] = 3, no solution 2, try to find the value of A

Given the equation about x [(AX) / X-1] - [2 / (1-x)] = 3, no solution 2, try to find the value of A

What you want to ask is the value of a when the equation has no solution, right? If it is, then the value of a is - 2, you just need to move the term, move (x-1) to the right of the equal sign, and substitute x = 1 to get the value of a, because in the original equation, X cannot be 1, otherwise the denominator is meaningless, then the result is the increasing root of the original equation

If the equation AX-1 / x + 1-2 = 0 about X has no solution, then the value of a is?
RT

(AX-1) / (x + 1) - 2 = 0 (1) when the denominator is 0, a is all real numbers when x = - 1
(aX-1)/(X+1)=2
aX-1=2X+2
(A-2) x = 3 when a = 2, there is no solution