As shown in the figure, ab ∥ DC, ad ∥ BC, be ⊥ AC in E, DF ⊥ AC in F, prove: be = DF

It is proved that: ∵ ab ∥ DC, ad ∥ BC, ∥ quadrilateral ABCD is a parallelogram, ∥ DC = AB, ∥ DCA = ∥ BAE, in △ DFC and △ BEA, ≌ DFC = ≌ BEA, ∥ be = DF

In hexagon ABCDEF, a = angle, B = angle, C = angle, d = angle, e = 120 degrees, AB + BC = 11, FA-Cd = 3, BC + ed =?

Let AB = x, then BC = 11-x. similarly, let FA = y, then CD = Y-3 extend BC, De, FA at the same time, so that they intersect each other. Then a large equilateral triangle and three small equilateral triangles with AB, CD, EF as side lengths can be obtained (because the three angles are all 60 degrees)

If a = b = C = D = e = f, AB + BC = 11, FA CD = 3, then BC + de =?

How much is 1.25 times 0.72? And check

Five monkeys had a pile of peaches. When the first one came, he ate and took away five more peaches on average. When the second one came, he ate and took away five more peaches. How many peaches are there?

There are two solutions
（1）
The fifth power of 5 + 1-5 = 3121
Give these monkeys four peaches first,
The first monkey had four more peaches, which were just divided into five parts. He took his own part (one more peach in a pile, and left four peaches for the second monkey);
The second monkey had four more peaches, which were just divided into five parts, and took his own part (one more in a pile, and the four peaches given to him were left to the third monkey);
.
The fifth monkey had four more peaches, which were just divided into five parts. He took his own part (one more peach in a pile, and left the four peaches for the sixth monkey);
.
That is to say, with these four peaches, each time the monkeys can be divided into five parts on average. It can be seen that the original total number must be a multiple of 5 to the 5th power, that is 3125, so there were 3121 peaches
（2）
Suppose there are x pick, first lend them 4 peaches, so you can share 5, and don't have to lose 1 peach, every time you can share 5
At least 2 peaches per serving
X+4=2*5*5*5*5*5=3125
X=3121
It's the best way to borrow 4 peaches first. But it's difficult to understand

Please help to work out this interesting question
1000 soldiers form a circle and count from the beginning. Every second one is executed until the last one is left. In order to survive, which position should we stand?

The answer to this question is 977
1. Get the total number n;
2. Find out the m-th power of the maximum 2 not exceeding n, and record it as M;
3. You can get the answer by substituting the formula I put forward!
The formula is as follows
X = 2 * (n-m) + 1 (x is the required number)
Consider 1000 people for circular circulation,
Because 1000 can be divided by 8, so after the first three cycles, the rest is 1,9 ,8n-7,…… ,993
Only 125 people,
According to the conditions of the title, we can deduce that the last remaining is: 8 * 123-7 = 977

Urgent a trouble, clear help me calculate this account
How many yuan will be deducted for 100 fast money, 8 fast money and 853 fast money?
This process helps me to be clear

800 buckles 64
50 buckles 4
1 Deduction 0.08 3 deduction 0.24
853 deduction 64 + 4 + 0.24 = 68.24

If you can put 5 bags of rice in each cubic meter of space, and each bag weighs 50 kg, how many tons of rice can be stored in this storage room?

V = 8 * 6 * 4.5 = 216 M3
216 * 5 * 50 = 54000kg = 54t

How many feet is one meter five?
One meter fifty-two
How to calculate it?
Clearly, I'll add more points,

1 meter = 3 feet
One meter five = 4.5 feet (1.5 * 3)
1m 52 = 4.56 (1.52 * 3)

Width 89 cm, length 1 meter 98 equal to how many square meters

(89 / 100) * 1.98 = 1.7622 square meters 1.7622 * 530 = 933.966 yuan

As shown in the figure, ab ∥ DC, ad ∥ BC, be ⊥ AC in E, DF ⊥ AC in F, prove: be = DF