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There are three points a, B and C on the straight axis, where the coordinates of points a and B are - 3 and 6 respectively, and | CB | = 2 If there are three points a, B and C on the straight axis, where the coordinates of points a and B are - 3 and 6 respectively, and | CB | = 2, then | ab | =?, and the coordinates of point C are? But the coordinate of the answer point C is only 4... Is the answer wrong?
Because a is - 3, B is 6,
So | ab | = 9,
Because | CB | = 2,
So the coordinates of C can be left or right of point B,
So the coordinates of point C are 4 or 8
As shown in the figure, O is the intersection of diagonal AC and BD of parallelogram ABCD. If vector AB = a, vector BC = B, OD = C, it is proved that C + A-B = vector ob
Detailed process, thank you
I drew a picture according to your description. I don't know if the picture is right
First of all, let's make clear the relationship between vectors. According to the principle of translatable vectors, in the parallelogram ABCD, OD = Bo = C, BC = ad = B, do = ob
So c + a = od + AB = Bo + AB = AB + Bo = Ao
Therefore, C + A-B = ao-bc = ao-ad = do = ob
I don't know if it can make you understand that I did it myself. I hope it can help you~
Given that O is the intersection of diagonal AC and BD of parallelogram ABCD, if vector AB = a, vector BC = B, vector od = C, try to prove that C + A-B = vector ob
Very simple: C + A-B = od + ab-bc = od + DC + CB = OC + CB = ob (all above are vectors)
If M is a moving point in or on the boundary of a square ABCD with side length 2, and N is the midpoint of side BC, then the maximum value of | vector an + vector am |
Establishing coordinate system with D point as origin
A(0,2),B(2,2),C(2,0),D(0,0),N(2,1)
Let m (x, y) x, y ∈ [0,2]
AN=(2,-1),AM=(x,y-2)
AN*AM=2x-y+2
When x is the largest and Y is the smallest, an * am is the largest
So x = 2, y = 0, take the maximum
AN*AM=6
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