Cut a cuboid 12 cm long, 9 cm wide and 5 cm high into two cuboids. What is the maximum sum of the surface area of the two cuboids? What's the minimum square centimeter?

① 2 × (12 × 9 + 9 × 5 + 12 × 5) + 2 × (12 × 9), = 2 × 213 + 2 × 108, = 426 + 216, = 642 (square centimeter); ② 2 × (12 × 9 + 9 × 5 + 12 × 5) + 2 × (5 × 9), = 2 × 213 + 90, = 516 (square centimeter). A: the sum of the surface area of the two cuboids is 642 square centimeter at most and 516 square centimeter at least

Cut a cuboid 12 cm long, 9 cm wide and 5 cm high into two cuboids. What is the maximum sum of the surface area of the two cuboids? What's the minimum square centimeter?

Two cuboids with length, width and height of 12cm, 8cm and 5cm are put together to form a large cuboid. What is the surface area of the large cuboid?

Does this require the maximum surface area, or is it all possible?

Calculate the surface area of a cylinder. A small cylinder is on the top and a large cylinder is on the bottom. The diameter of the small cylinder is 2cm, the height is 6cm, and the diameter of the large cylinder is 5cm
8cm height is also 8cm surface area

The surface area of small cylinder is 3.14 × 1 & # 178; × 6 = 18.84cm & # 179;
The surface area of large cylinder is 3.14 × 4 & # 178; × 8 = 402.12cm & # 179;
The area of the bottom of the small cylinder is 3.14 × 1 & # 178; = 3.14cm & # 178;
The area of the bottom of the large cylinder is 3.14 × 4 & # 178; = 50.26cm & # 178;
The surface area of the figure is (18.84 + 402.12) - 3.14 × 2-50.26 = 364.42cm & # 178;
A. the surface area is 364.42cm-178;

Cut a cuboid 12 cm long, 9 cm wide and 5 cm high into two cuboids. What is the maximum sum of the surface area of the two cuboids? What's the minimum square centimeter?