In the triangle ABC, D is the midpoint of BC, AC = 3ec, the area of CDE is 6 square centimeters, what is the area of ABC

In the triangle ABC, D is the midpoint of BC, AC = 3ec, the area of CDE is 6 square centimeters, what is the area of ABC


Let BC = x, ad = y, do EF perpendicular to BC at point E, then EF = 1 / 3aD = 1 / 3Y, CD = 1 / 2BC = 1 / 2x, because SCDE = 1 / 2x1 / 3yx1 / 2x = 6, then xy = 72, SABC = 1 / 2xadxbc = 1 / 2XY = 36



We know that the triangle ABC, D is the midpoint on the side of BC, AE = 1 / 3bC. If the area of the triangle CDE is 5 square centimeter, then three
Natural number 121219000941014 They all have a common characteristic. The reverse is the original number. How many odd five digit numbers have this characteristic?


Any three digit number can form a five digit number you need. Just reverse the first two digits of the three digit number to the last two digits. The three digit number 100-999 can form a five digit number. For example, 100 constitutes 1000, 1999 constitutes 99999



Given that the distance between the center of gravity g of △ ABC and the midpoint D on the side of BC is 2, then the length of the center line ad is______ .


∵ G is the center of gravity of △ ABC, ∵ Ag = 2Gd = 4; ∵ ad = Ag + GD = 6



In known triangle ABC, ab = AC = 18cm, the area of triangle is 81 square cm, P is any point on BC, and the distances from P to AB and AC are xcm and YCM respectively
So what is x + y?


If AP is connected, the area of triangle ABC = the area of triangle ABP + the area of triangle ACP,
Because the distances from P to AB and AC are xcm and YCM respectively,
And ab = AC = 18cm, the area of triangle ABC is 81 square centimeters,
So (18x / 2) + (18y / 2) = 81,
That is: 9 (x + y) = 81,
So x + y = 9