How to find the value range of the slope of a straight line. For example, find the value range of the slope of the straight line MX - (m ^ 2 + 1) y = 4m The slope range of MX - (m ^ 2 + 1) y = 4m

How to find the value range of the slope of a straight line. For example, find the value range of the slope of the straight line MX - (m ^ 2 + 1) y = 4m The slope range of MX - (m ^ 2 + 1) y = 4m

k=m/(m²+1)
It is easy to know that Hengyou - 1 / 2 ≤ M / (M & # 178; + 1) ≤ 1 / 2
That is to say, Hengyou - 1 / 2 ≤ K ≤ 1 / 2

Given that the absolute value of the slope of a straight line is equal to 1, calculate the inclination angle of the straight line

Let a be the inclination angle of a straight line
Then, there is | Tana | = 1
Tana = 1 or Tana = - 1
0

Given that the absolute value of the slope of the line L is equal to 3, then the inclination angle of the line is______ ．

∵ the absolute value of the slope of the straight line L is equal to 3, let the inclination angle of the straight line be α, then Tan α = ± 3, and α ∈ [0 ° 180 °), so α = 60 ° or α = 120 °, so the answer is: 60 ° or 120 °

Why is the absolute value of the slope of the line equal to the internal resistance of the power supply? Is the ratio of the terminal voltage to the current not the external resistance?

The slope is the short-circuit current to I in U / I. at this time, the power supply voltage is all added to the internal resistance of the power supply. The external circuit resistance is zero, and there is no link voltage, so the slope is the internal resistance

The triangle ABC ∽ triangle DEF is known, and the ratio of the three sides of the triangle ABC is 3:5:7, and the maximum side length of the triangle DEF is 15cm
. find the perimeter of triangle def

Triangle ABC ∽ triangle def, and the ratio of three sides of triangle ABC is 3:5:7, so the ratio of three sides of triangle DEF is 3:5:7
The maximum side length of triangle DEF is 15cm, so the three sides are 75 / 7 45 / 7 15
Perimeter of triangle def = 75 / 7 + 45 / 7 + 15 = 225 / 7

It is known that the three sides of △ ABC are 6cm, 7.5cm and 9cm respectively, and one side of △ DEF is 5cm
When the other sides of △ def are in the following groups, the two triangles are similar () a.2cm; 3cm b.4cm; 6cm c.6cm; 7cm d.7cm; 9cm

B divides the known three sides into 4:5:6, and the result is obviously B

In the known triangle ABC, ab = 5cm, BC = 7cm, AC = 10cm, △ ABC is similar to △ def, and its circumference is 33cm. Find the length of each side of △ def

AB:DE=BC:EF=AC:DF
DE=5x,EF=7x,DF=10x
=>5x+7x+10x=33
=>x=3/2
=>DE=15/2,EF=21/2,DF=15

The three sides of triangle ABC are 4cm, 5cm and 6cm respectively,
Take three points a, B and C as the center and 1cm as the radius to form three small sectors (all inside the triangle) with the three sides of the triangle
Formula

The sum of the inner angles of the triangle is 18O degrees, so the sum of the two sector angles is L80 degrees to form a semicircle with a radius of 1cm s = L / 2 * 3. L4 * 1 * 1 = L / 2 μ cm ^ 2

The height of straight triangular prism abc-a1b1c1 is 6cm, the side length of bottom triangle is 3cm, 4cm, 5cm,
Take the inscribed circle of the upper and lower bottom as the bottom, dig out a cylinder, and calculate the surface area and volume of the remaining geometry

V = V triangular prism-v cylinder
=6×6-6π
=36－6π
S = s triangular prism + s cylinder side - 2S inscribed circle
=﹙3＋4＋5﹚×6＋2×6＋6×2π-2π
=84＋10π

The three sides of △ ABC are 4cm and 5cm.6cm in turn. Take points a, B and C as the center of the circle and 1cm as the radius to make an arc and a small triangle sector (all inside the triangle), and calculate the area of the three sectors

The radii of these three sectors are all 1 cm, and the sum of central angles = △ ABC, the sum of internal angles = 180 degrees,
Therefore, these three sectors can be assembled into a semicircle with a radius of 1cm, and its area = π * 1 & sup2; / 2 = π / 2 (CM & sup2;)