As shown in the figure, points a, O and B are on the same straight line, ∠ AOC = 1 / 2 ∠ BOC + 30 °, OE bisects ∠ BOC, and calculates the degree of BOE I don't know how to draw or dictate a straight line. The right side is B and the left side is a. there is o point in the middle, with o as the point, extending from the upper right corner to e and from the upper left corner to C~

As shown in the figure, points a, O and B are on the same straight line, ∠ AOC = 1 / 2 ∠ BOC + 30 °, OE bisects ∠ BOC, and calculates the degree of BOE I don't know how to draw or dictate a straight line. The right side is B and the left side is a. there is o point in the middle, with o as the point, extending from the upper right corner to e and from the upper left corner to C~


Because a, O and B are on the same straight line, ∠ AOC + ∠ BOC = ∠ AOB = 180 ° i.e. ∠ AOC = 180 °- ∠ BOC from ∠ AOC = 1 / 2 ∠ BOC + 30 °, we can get 180 ° - ∠ BOC = 1 / 2 ∠ BOC + 30 ° so, ∠ BOC = 100 ° OE bisection ∠ BOC, so, ∠ BOE = 1 / 2 ∠ BOC = 50 °



As shown in the figure, the angle AOB = 180 ° od and OE are bisectors of the angle AOC and the angle BOC respectively, and the angle doc is 30 ° larger than the angle Coe. calculate the degree of the angle AOE


If AOB = 180 ° and OD and OE are bisectors of AOC and BOC respectively, then ∠ AOC + ∠ BOC = 180 ∠ AOC = ∠ AOD + ∠ doc = 2 ∠ doc ∠ BOC = ∠ COE + ∠ BOE = 2 ∠ EOC, then ∠ AOC + ∠ BOC = 180 = 2 ∠ doc + 2 ∠ EOC, then ∠ doc + ∠ EOC = 90, because ∠ doc - ∠ EOC = 30, then ∠ doc = 60 ∠ EOC = 3



As shown in the figure, ∠ AOB = 120 °, OD bisection ∠ BOC, OE bisection ∠ AOC. ① calculate the degree of ∠ EOD. ② if ∠ BOC = 90 °, calculate the degree of ∠ AOE


(1) ∫ AOB = 120 °, OD bisection ∫ BOC, OE bisection ∫ AOC, ∫ EOD = ∫ doc + ∫ EOC = 12 (∫ BOC + ∫ AOC) = 12 × 120 ° = 60 °; (2) ∫ AOB = 120 °, ∫ BOC = 90 °, ∫ AOC = 120 ° - 90 ° = 30 °, ∫ OE bisection ∫ AOC, ∫ AOE = 12 ∫ AOC = 12 × 30 ° = 15 °