If P (2,2) is the midpoint of AB, then the equation of parabola C is______ ．

If P (2,2) is the midpoint of AB, then the equation of parabola C is______ ．

Let the parabolic equation be y2 = 2px, and the equation of x2-2px = 0 ∫ XA + XB = 2p ∫ XA + XB = 2 × 2 = 4 ∫ P = 2 ∫ parabolic C be y2 = 4x, so the answer is: y2 = 4x

If P (2,2) is the midpoint of AB, then the equation of parabola C is______ ．

Let the parabolic equation be y2 = 2px, and the equation of x2-2px = 0 ∫ XA + XB = 2p ∫ XA + XB = 2 × 2 = 4 ∫ P = 2 ∫ parabolic C be y2 = 4x, so the answer is: y2 = 4x

The parabolic equation with vertex at origin and focus f (0, - 1) is
How to solve this problem, according to what, please write a detailed part, thank you, must be detailed

The parabola whose vertex is at the origin and focus is f (0, - 1) opens downward, so - P / 2 = - 1, P = 2, and the parabola equation is x ^ 2 = - 2PY = - 4Y

If the vertex of the parabola is at the origin and the focus coordinate is (- 1,0), then the parabola equation is

y^2=-4x