In the rectangular coordinate system, there are two intersections between the parabola y = ax ^ 2 + BX + C and the X axis, and the distance from the intersection to the origin is greater than 1 Then the minimum value of ABC is (), and a + B + C = ()

In the rectangular coordinate system, there are two intersections between the parabola y = ax ^ 2 + BX + C and the X axis, and the distance from the intersection to the origin is greater than 1 Then the minimum value of ABC is (), and a + B + C = ()


The problem is wrong, the minimum value can be infinitesimal, such as a (- 30000,0) B (- 10000,0) vertex (- 2000010000)
If it is the absolute value of ABC, it can also be wireless close to zero, the vertex (0,0.000000000 1) can be



It is known that the intersection of the parabola y = ax & sup2; + 2x + C and X axis is on the right side of the origin, and the point m (a, c) is in the () quadrant. Why?
1. It is known that the intersection of the parabola y = ax & sup2; + 2x + C and X axis is on the right side of the origin, and the point m (a, c) is in the () quadrant. Why?
2. No matter what real number the independent variable x takes, the function value of quadratic function y = 2x & sup2; - 6x + m is always positive, then the value range of M is (). Why?
3. The vertex of the parabola y = x & sup2; - 2x + m is on the x-axis. Why do we find its vertex coordinates and symmetry equation?


Because the intersection of the parabola and the x-axis is on the right side of the origin, the axis of symmetry x = - B / 2a is also on the right side of the origin
So - B / 2A 〉 0, B = 2
That is - 1 / a > 0
So a 〈 0
So the parabola opens down
The intersection point with X axis should be greater than 0 on the right side of the origin
So when x = 0, the intersection of the parabola and the y-axis, y = C, is on the negative half axis of the y-axis
So C 〈 0
So m (a, c) is in the third quadrant



If we know that the intersection points of the parabola y = AX2 + 2x + C and X axis are on the right side of the origin, then the point m (a, c) is on the second side___ Quadrant


Let X1 and X2 be the roots of the equation AX2 + 2x + C = 0, then the relationship between the roots and the coefficients shows that X1 + x2 = - BA = - 2A, x1x2 = Ca, the intersection points of ∵ function and X axis are on the right side of the origin, ∵ X1 + X2 > 0, x1x2 > 0, ∵ a < 0, C < 0, and the point m (a, c) is in the third quadrant



As shown in the figure, the parabola passes through three points a (4,0), B (1,0), C (0, - 2). (1) find out the analytical formula of the parabola; (2) P


Y = AX2 (quadratic) + BX + C, substituting into three points, C = - 2, a = - 1 / 2, B = 5 / 2
Y = (- 1 / 2) X2 (2nd power) + (5 / 2) X-2
And then there's no graph, P doesn't know