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Focus coordinates of parabola x = 1-4t ^ 2 y = 3T (t as parameter), quasilinear equation Parabola x = 1-4t ^ 2 The focal coordinate of y = 3T (t is a parameter) and the Quasilinear equation
x=1-4t^2
y=3t
∴x=1-4y²/9
So y ^ 2 = (1-x) 9 / 4
p=-9/8
So the intersection is (7 / 16,0)
Alignment x = 25 / 16
A = (3,1), B = (Sint, cost), and a ‖ B, (1) find the value of ant (2) 2Sin ^ 2T + Sint * cost cos ^ 2T
The first question is that a is parallel to B, so 3cost = Sint, tant = 3
The original formula of the second question is 1 / 2-3cos2t / 2 + 1 / 2sin2t
And then the universal replacement cos2t = - 5 / 4, sin2t = 2 / 3
Original formula = 65 / 24
Solving parametric equations of hyperbola and parabola (including various cases with focus on two axes)
The parametric equation of a circle x = a + R cos θ y = B + R sin θ (a, b) is the center coordinate of the circle, R is the radius of the circle, and θ is the parameter
The parametric equation of ellipse x = a cos θ y = B sin θ A is the long half axis, B is the short half axis, and θ is the parameter
The parametric equation of hyperbola x = a sec θ (secant) y = B Tan θ A is the real half axis length B is the imaginary half axis length and θ is the parameter
The parameter equation of parabola x = 2pt ^ 2 y = 2pt P indicates that the distance from focus to collimator t is a parameter
The parametric equation x = x '+ tcosa, y = y' + Tsina, X ', y' and a denote that the straight line passes through (x ', y'), and the inclination angle is a, t is the parameter
The parametric equation x = T & # 179; + 2T & # 178; / T & # 178; - 1 y = 2T & # 179; + T & # 178; / T & # 178; - 1 is transformed into ordinary equation
RELATED INFORMATIONS
- 1. It is known that the equation of parabola C is Y & # 178; - 2px-2ysin & # 178; the fourth power of θ + sin θ + 2pcos θ = 0 (1) find the coordinates of focus F of parabola C (2) make a straight line L with an inclination angle of 45 ° through F and intersect the parabola C at two points ab. when θ changes, calculate the abscissa range of the intersection of the middle vertical line of the chord AB and the X axis
- 2. The equation of motion of the point is: x = 3T, y = 4t-5t & # 178; find the tangential acceleration when t = 0
- 3. When the object moves with damping, the law of motion is x = e ^ (- 2t) * sin (3T + π / 6), then when t = 0
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- 9. It is known that the parametric equation of C is x = 3cost y = 3sint (t is the parameter), and the tangent of C at point (0,3) is o If the origin of angular coordinate is the pole and the positive half axis of X axis is the polar axis, the polar coordinate equation of O is?
- 10. If the polar coordinate equation of the curve is ρ & # 178; = 400 / (16cos & # 178; θ + 25sin & # 178; θ), the general equation of the curve is?
- 11. The parametric equation: x = t / (1-2T ^ 2), y = (1-2T ^ 2) / (1 + 2T ^ 2) is transformed into a general equation
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