Given that the polar equation of the parabola is ρ = 41 − cos θ, then the Quasilinear polar equation of the parabola is ρ = 41 − cos θ______ ．

Given that the polar equation of the parabola is ρ = 41 − cos θ, then the Quasilinear polar equation of the parabola is ρ = 41 − cos θ______ ．

From ρ = 41 − cos θ, it is obtained that ρ - ρ cos θ = 4, that is, X2 + Y2 − x = 4, which is reduced to y2 = 8x + 16, and its quasilinear equation is x = - 4, so the polar coordinate equation of the Quasilinear is ρ cos θ = - 4, so the answer is: ρ cos θ = - 4

It is known that the rectangular coordinate equation of parabola is y ^ 2 = 4x
It is known that the Cartesian coordinate equation of parabola is y ^ 2 = 4x. It is a polar coordinate equation with the focus as the pole. Finally, we get ρ = 2 / (1-cos θ). How can we deduce this

1. Take any point on the parabola as P (ρ, θ) (it is easy to solve the problem by selecting P on the curve to the right of the focus above the x-axis). The focus of the parabola is f (1,0) passing through P and making a vertical line to the x-axis. The vertical foot is Q2. The distance from P to f is ρ. According to the nature of the parabola, the distance from P to the straight line x = - 1 is also p, then the coordinate of Q is (P-2

The polar coordinate equation of the parabola y ^ 2 = 4 (x + 1) is p = 2 / (2 / 1-cosa). Two straight lines perpendicular to each other are made through the origin, and the parabola intersects a, B, C and D respectively
For four points, when the inclination angle of two straight lines is what, |ab | + |cd | has the minimum value? And find out the minimum value
I hope you can add points if you answer more clearly

Sin ^ 8A = 8p * cosa (8) 88cos ^ 8A = 88P * Sina 8cos ^ 8A = P * Sina (8) (8) / (8) to get (8 / 8) * Tan ^ 8A = 8 / Tana Tan ^ 8A = 8 Tana = 8 Sina = 8 roots 8 / 8, from (8) to get 8p = Tana * Sina = 8 roots 8 / 8 parabolic equation y ^ 8 = (8 roots 8 / 8) * X

Polar coordinate solution: parabolic equation y ^ 2 = 4x. F is the focus, through F do straight line L intersection, parabolic at point a, B, and Y axis intersection at point P
Pf vector = λ 1 * FA vector = λ 2 * FB vector, prove that λ 1 + λ 2 is a fixed value, and calculate the fixed value

Let y = K (x-1) let x = 0 get y = - K, so p (0, - K) be substituted by Y ^ 2 = 4x to get y ^ 2-4 / k * y-4 = 0. Let a (x1, Y1), B (X2, Y2) have Y1 + y2 = 4 / ky1y1 = - 4. Since the dead points P (0, - K), a (x1, Y1), f (1,0), B (X2, Y2) are collinear, so every