It is known that the quadratic function y = AX2 + BX + C (a ≠ 0) satisfies the following quantitative relationship between the independent variable x and the function value y X negative two thirds negative one negative half 0 half 1 half three Four fifths of Y minus two minus nine fourths of Y minus two minus five fourths of Y minus seven fourths of Y

It is known that the quadratic function y = AX2 + BX + C (a ≠ 0) satisfies the following quantitative relationship between the independent variable x and the function value y X negative two thirds negative one negative half 0 half 1 half three Four fifths of Y minus two minus nine fourths of Y minus two minus five fourths of Y minus seven fourths of Y


Select three groups of values (- 1, - 2); (0, - 2); (1,0) and substitute them respectively (because these numbers are convenient for calculation)
a-b+c=-2
c=-2
a+b+c=0
The results of solving equations
a=1
b=1
c=-2
The analytic formula is y = x ^ 2 + X-2



The partial corresponding values of the independent variable X of the quadratic function y ax 2 + BX + C and the function value y are as follows: X... - 2 - 102 t 5... Y... - 7
x...-2 -1 0 2 t 5 ...
y...-7 -2 1 1 -7 -14...
(1) (1) t = - (2) maximum value of quadratic function (3) if points a (x1, Y1) and B (X2, Y2) are two points on the image
And - 1 < x 1 < 0,4 < x 2 < 5 is the comparison of Y 1 and y 2
(2) Find the root of ax & # 178; + BX + C = 0——
(3) If the value range of independent variable x is - 3 ≤ x ≤ 3, then the value range of function value y is -


4a-2b+c=-7
a-b+c=-2
c=1
So the solution is a = - 1, B = 2, C = 1
By x = 0,2, y = 1
We obtain that the axis of symmetry is x = 1, and if x = - 2, y = - 7
So t = 4
Maximum value of quadratic function = 2
y2<y1
2. Root formula 1 + 2 ^ 0.5 1-2 ^ 0.5
The root number cannot be typed
3.-14→2