The function y = MX2 + x-2m (M is a constant), and the intersection of the image and X-axis has the following properties______ One

The function y = MX2 + x-2m (M is a constant), and the intersection of the image and X-axis has the following properties______ One

When m = 0, y = x, the intersection of image and X-axis has one

The image of function y = the square of MX + x-2m (M is a constant) and the number of focal points of X axis are_____

2

The parabola of quadratic function y = x2 + 4x + 3 moves up or down the absolute value of K and passes through a point after a unit length
The absolute value of the parabola moving up or down passes through the point after a unit length
How to understand C 〔 - 5,6 〕
Finding the minimum value of K and parabola

The absolute value of upward translation K is one unit length
Y=X2＋4X＋3+|k|
6=25-20+3+|k|
|K | = - 2 impossible
The absolute value of downward translation K is one unit length
Y=X2＋4X＋3-|k|
6=25-20+3-|k|
|k|=2

It is known that the image of a quadratic function is obtained by translating the parabola y = 2x ^ 2 along the x-axis. When x = - 1, y = 4
Solving the parabola analytic formula
Why does the value of X decrease with the increase of X

Y = 2x & # 178; the vertex is the origin, so the vertex is (m, 0) after translation, so it is y = 2 (x-m) & # 178; + 0 x = - 1, y = 4, then 4 = 2 (- 1-m) & # 178; - 1-m = ± √ 2 m = ± √ 2-1, so it is y = 2 (x - √ 2 + 1) & # 178; or y = 2 (x + √ 2-1) & # 178; y = 2 (x-m) & # 178; with the opening upward, the axis of symmetry x = m, so x

Fill in the blanks in junior three (about quadratic function)
When x = - 1, there is a maximum value of 2, and the distance between the two points and the X axis is 2

Because when x = - 1, the maximum value of the function is 2
So let y = a (x + 1) ² + 2 = ax & #178; + 2aX + A + 2
And because there is a maximum
So the opening is down, a

If the quadratic equation x2-x-n = 0 of X has no real roots, then the vertex of the parabola y = x2-x-n is at ()
A. First quadrant B. second quadrant C. third quadrant D. fourth quadrant

∵ the symmetry axis X of the parabola y = x2-x-n = - − 12 × 1 = 12, ∵ we know that the vertex of the parabola is on the right side of the y-axis, and ∵ the quadratic equation x2-x-n = 0 with respect to X has no real root, ∵ the y = x2-x-n with the opening upward has no intersection with the x-axis, and the vertex of the parabola y = x2-x-n is in the first quadrant

It is known that the parabola y = AX2 (a ≠ 0) and the line y = x + 4 intersect at two points a and B, and (2,6) find the coordinates of point B
Y = the square of ax

Because a (2,6) is the intersection of parabola y = ax ^ 2 (a ≠ 0) and straight line y = x + 4
So a (2,6) is a point on the parabola y = ax ^ 2 (a ≠ 0)
Then 6 = a * 2 ^ 2, that is, a = 3 / 2
So the analytic formula of parabola y = ax ^ 2 (a ≠ 0) is: y = 3 / 2 x ^ 2 (a ≠ 0)
Because the parabola y = 3 / 2 x ^ 2 (a ≠ 0) and the line y = x + 4 intersect at a (2,6)
So 3 / 2 x ^ 2 = x + 4
That is, 3x ^ 2-2x-8 = 0
The solution is X1 = 2, X2 = - 4 / 3
Substituting x2 = - 4 / 3 into y = x + 4 (or y = 3 / 2 x ^ 2 (a ≠ 0))
So y = - 4 / 3 + 4 = 8 / 3
In conclusion, the coordinates of point B are (- 4 / 3,8 / 3)

It is known that the distance between a point on the image with positive scale function y = KX (k > 0) and the origin is equal to 5,
The area of the line segment from this point to the perpendicular foot, the x-axis and the figure enclosed by this image is equal to 6. The analytic expression of this positive scale function is obtained

Let this point be (a, b) a ^ 2 + B ^ 2 = 5 ^ 2 1 / 2 ab = 6 B = Ka a = 3 or 4 B = 4 or 3 K = 4 / 3 or 3 / 4, then y = 4 / 3 x or y = 3 / 4 x ^ 2 is square

It is known that the distance between a point on the image of the positive scale function y = KX (k > 0) and the origin is equal to 5. From this point, a vertical line is drawn. The area of the triangle surrounded by the vertical line, the function image and the x-axis is 6

Let this point be (a, b)
a^2+b^2=5^2
1/2ab=6
b=ka
a=3 or 4 b= 4 or 3 k=4/3 or 3/4
The solution is y = 4 / 3 x or y = 3 / 4 X

If the distance from a point to the x-axis of the image is three times of the distance from the point to the y-axis, then the value of K is K___

3